to practice for an Ironman competition John swim 0.86 kilometers each day for three weeks how many meters did he swim in those 3
2 answers:
He swim in those 3 weeks for 18060 meters
<h3>Further explanation </h3>Swimming is an individual or team racing sport that needs the use of one's entire body to move through water. This sport takes place in pools or open water. During each the event portion , swimmers must swim the strokes legally. Swimmers must finish the butterfly and breaststroke laps with two-hand-touches and finish the backstroke lap on their backs.
Ironman Triathlon is one of a series of long-distance triathlon races. Ironman Triathlon is organized by the World Triathlon Corporation (WTC), consisting of a 2.4-mile (3.86 km) swim, a 112-mile (180.25 km) bicycle ride and a marathon 26.22-mile (42.20 km) run.
To practice an Ironman competition, John swim 0.86 kilometers each day for three weeks. How many meters did he swim in those 3 weeks?
John swam 860 meters each day. Therefore
To practice for an Ironman competition John swim 0.86 kilometers each day for three weeks he swim in those 3 weeks for 18060 m
<h3>Learn more</h3>- Learn more about Ironman Triathlon brainly.com/question/13229667
- Learn more about swim brainly.com/question/7486859
- Learn more about Ironman competition brainly.com/question/1746939
<h3>Answer details</h3>
Grade: 9
Subject: Math
Chapter: Ironman competition
Keywords: Ironman Triathlon, swim, Ironman competition, Triathlon, competition
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Once this rewriting is done, getting the total length is quite trivial, since all measurements are in the same unit, and we can simply sum everything:
Answer:
Answer: 5/12 or approx. 0.42
Step-by-step explanation:
The ball will displace as much water as its volume.
Meaning, the volume of the ball and the volume of the increase in water in the barrel will be equal.
Volume of a sphere:
The radius is half the diameter. The diameter of the sphere is 10, thus:
5^3 = 5*5*5 = 25*5 = 125
The volume of a cylinder, which will be the shape of the increase in water, is the following:
We know the radius r, as we know the diameter.
We are looking for the height of the cylinder, h, as that will be the height of the water rise.
Since we know these 2 volumes are the same, we'll set them equal to each other and solve the equation:
We can get rid of pi by dividing both sides by pi:
And now divide both sides by 400:
Just reversing it and putting h to the left:
I see that I can divide both the numerator and the denominator by 4:
I'll now divide both the numerator and the denominator by 25 to simplify the expression:
Answer: The water rises by 5/12 (five twelfths).
If I want an approximate decimal answer, I can simply run this expression in a calculator:
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