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babymother [125]
2 years ago
13

Saira weights 25 pounds more than umbar . If together they weight 205 pounds. What is the weight of saira

Mathematics
1 answer:
goblinko [34]2 years ago
6 0
To solve this, you can create an equation. Say the weight of Umbar is x, then Saira weighs x+25. Together they weigh 205. So, you get the equation

x+x+25=205

Then solve for x. 

2x+25=205
2x=180
x=90

Then to find Saira's weight, add 25 to Umbar's weight. 

90+25=115.
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Answer:

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n=369

Step-by-step explanation:

1) Notation and definitions

X=40 number of the selected labourers opt for a new incentive scheme.

n=100 random sample taken

\hat p=\frac{40}{100}=0.4 estimated proportion of the selected labourers opt for a new incentive scheme.

p true population proportion of the selected labourers opt for a new incentive scheme.

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

The population proportion have the following distribution

p \sim N(p,\sqrt{\frac{p(1-p)}{n}})

2) Solution tot he problem

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 95% of confidence, our significance level would be given by \alpha=1-0.95=0.05 and \alpha/2 =0.025. And the critical value would be given by:

z_{\alpha/2}=-1.96, z_{1-\alpha/2}=1.96

The margin of error for the proportion interval is given by this formula:  

ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}    (a)  

And on this case we have that ME =\pm 0.05 and we are interested in order to find the value of n, if we solve n from equation (a) we got:  

n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}   (b)  

And replacing into equation (b) the values from part a we got:

n=\frac{0.4(1-0.4)}{(\frac{0.05}{1.96})^2}=368.79  

And rounded up we have that n=369

8 0
2 years ago
Which rule should be applied to reflect f(x)=x^3 over the y-axis?
Anna11 [10]
To make a reflection over the y axis, make the whole equation negative. 
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f(x) = -x^3
7 0
2 years ago
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Paraphin [41]

Answer:

The value of x is, x= \frac{17N+r}{34-N}

Explanation:

Given: N(17+x)=34x-r

Distributive Property states that when a number is multiplied by the sum of two numbers, the first number can be distributed to both of those numbers and multiplied by each of them separately.

If a\cdot(b+c) =a\cdot b + a\cdot c

Now, using distributive property on left hand side of the given expression as:

N\cdot 17+N\cdot x = 34x-r or 17N+Nx = 34x-r

Addition Property of equality state that we add the same number from both sides of an equation.

Add r to both sides of an equation:

17N+Nx+r=34x-r+r

Simplify:

17N+Nx+r=34x

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Subtract Nx from both sides of an equation;

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Simplify:

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or

17N+r=x(34-N)

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Divide by (34-N) to both sides of an equation;

\frac{17N+r}{34-N}= \frac{x(34-N)}{34-N}

On Simplify:

x= \frac{17N+r}{34-N}





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Luba_88 [7]

Answer:

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2 years ago
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