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natita [175]
2 years ago
13

Sodium azide decomposes rapidly to produce nitrogen gas. 2 nan3(s) → 2 na(s) + 3 n2(g) what mass of sodium azide will inflate a

60.3 l airbag for a car to a pressure of 1.78 atm at 30.0 °c? (r = 0.08206 l×atm/mol×k)
Chemistry
1 answer:
ryzh [129]2 years ago
7 0
We solve for n of N₂ gas from the ideal gas equation:

PV=nRT
n = PV/RT
n = (1.78 atm)(60.3 L)/(<span>0.08206 L-atm/mol-K)(30 + 273 K)
</span>n = 4.32 mol N₂

Through stoichiometric calculations,
Mol NaN₃ = 4.32 mol N₂ * 2 mol NaN₃/3 mol N₂ = 2.88 mol

Since the molar mass of sodium azide is 65 g/mol,

Mass = 2.88 mol * 65g/mol = <em>187.2 g NaN₃</em>
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How long will it take 10.0 mL of Ne gas to effuse through a porous barrier if it has been observed that 125 minutes are required
cupoosta [38]

Answer:

88.8 minutes

Explanation:

Graham's law of diffusion relates rate of difusion by the following formula

Rate1 / rate 2 = √( Mass of argon / Mass of Neon)

Where rate = volume divided by time

Rate 1 = 10 ml / t1

Rate 2 = 10 ml / t2

Rate 1/ rate 2 = 10 ml / t1 ÷ 10 ml/ t2 = t2/ t1

t2/t1 = √(Mass of argon / mass of Neon) = √( 39.984/20.179)

125 / t1 = 1.4026

t1 = 125 / 1.4026 = 88.8 minutes

7 0
2 years ago
Elena has two magnets. She puts one under a piece of paper. She holds the other one above it. The magnets attract each other. Th
Sonbull [250]
A) Magnets can attract through solid materials.
6 0
2 years ago
Which of the samples described below contains the FEWEST atoms? No calculation is needed to answer this question.
Monica [59]

Hello!

To do this, use the molar mass. This is how much a mole of an atom weighs. A mole is 6.02214076×10²³ atoms.

Molar masses of:

Se: 78.96 g/mol

Cu: 63.546 g/mol

Ba: 137.327 g/mol

Now, the element with the highest molar mass will have the fewest atoms. This is because the element weighs more, so therefore for the same amount of mass, there will be less of the element needed to reach that mass.

Therefore, 10g of Ba would have the fewest number of atoms.

Hope this helps!

6 0
2 years ago
Use the virtual lab to prepare 150.0 ml of an iodine solution with a concentration of 0.06 g/ ml from the bottle of 0.12g/ml iod
son4ous [18]

Answer:

Explanation:

In 150 ml of .06 g / ml solution , gram of iodine = 150 x .06 g = 9 g

Let volume of given concentration of .12 g / ml required be V

In volume V , gram of iodine = V x .12 g

According to question

V x .12 = 9 g

V = 9 / .12 = 75 ml

So, 75 ml of .12 g/ml will be taken and it is diluted to the volume of 150 ml to get the solution of required concentration .

8 0
2 years ago
If 3.491 grams of the precipitate was formed, how many moles of strontium bromide were reacted
AVprozaik [17]
The balanced chemical equation that represents the reaction is as follows:
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</span>
From the periodic table:
mass of silver = 108 grams
mass of bromine = 80 grams

molar mass of silver bromide = 108 + 80 = 188 grams

number of moles = mass / molar mass
number of moles of produced precipitate = 3.491/188 = 0.018 moles

From the balanced equation:
1 mole of  strontium bromide produces 2 moles of silver bromide. Therefore, to calculate the number of moles of <span>strontium bromide that produces 0.018 moles of silver bromide, you will just do a cross multiplication as follows:
amount of </span><span>strontium bromide = (0.018x1) / 2 = 9.28 x 10^-3 moles</span>
4 0
2 years ago
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