Let s = sale
Let h = hours
The ratio is s to h, which can be written as a fraction as 24/6.
If you meant:
(2ya)^4=16y^8 raise the left side to the power of four
16y^4*a^4=16y^8 divide both sides by 16y^4
a^4=y^4 take the quartic root of both sides
a=±y
To find the cofactor of
![A=\left[\begin{array}{ccc}7&5&3\\-7&4&-1\\-8&2&1\end{array}\right]](https://tex.z-dn.net/?f=A%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D7%265%263%5C%5C-7%264%26-1%5C%5C-8%262%261%5Cend%7Barray%7D%5Cright%5D)
We cross out the Row and columns of the respective entries and find the determinant of the remaining
matrix with the alternating signs.
























Therefore in increasing order, we have;

Given that:
The company uses its cargo vans to deliver packages to locations at a 75-mile radius from the warehouse.
If delivery location is within 8 miles of the delivery boundary, a cargo van will still be used.
To find: The inequality to represent the instances when a vehicle other than a cargo van is used.
Solution:
Let x is the distance of a location from the warehouse.
Cargo van will be used if delivery location is within 8 miles of the delivery boundary.
Minimum distance for delivery = 75-8 = 67 miles.
Maximum distance for delivery = 75+8 = 83 miles.
So, the company uses cargo vans for any distance in the range 67 miles to 83 miles. So,

Therefore, the required inequality is
.
1/6 of an hour is 10 minutes. For a precise answer, convert it to seconds. You will end up with 600 seconds. Divide the area of the sheet by 600 seconds.
1260/600 ~ 2
With this result, Samantha glued approximately 2 stickers every second.