The x-intercept is a point on the x-axis.
y=0 at every point on the x-axis.
-2x + 1/2(0) = 18
-2x = 18
Divide each side by -2 : x = -9
We have two equations that were solved by Nikki and Jonathon:
Equating the above two:
⇒ 1.3x + 1.6 = -2.7x + 3.2
⇒ 4x = 1.6
⇒ x = 0.4
Hence, substituting the value of x in one of the equations we get:
y = 1.3×0.4 + 1.6 = 2.12
So the solution is (0.4, 2.12)
Jonathon's solution was (0.4, 2.12) and Nikki's was (2.25, 0.5). Hence Jonathon gave the correct solution.
Answer:
<em>The correct answer is: False</em>
Step-by-step explanation:
<u>If the sum of the opposite angles in a quadrilateral is 180°</u>, then a circle can be circumscribed about the quadrilateral.
Here, 
but, 
So, a circle can't be circumscribed about the given quadrilateral.
2. $5.10
4. 18%
I don't feel like doing 5 right now I'm watching hulu haha
Answer:
y2 = C1xe^(4x)
Step-by-step explanation:
Given that y1 = e^(4x) is a solution to the differential equation
y'' - 8y' + 16y = 0
We want to find the second solution y2 of the equation using the method of reduction of order.
Let
y2 = uy1
Because y2 is a solution to the differential equation, it satisfies
y2'' - 8y2' + 16y2 = 0
y2 = ue^(4x)
y2' = u'e^(4x) + 4ue^(4x)
y2'' = u''e^(4x) + 4u'e^(4x) + 4u'e^(4x) + 16ue^(4x)
= u''e^(4x) + 8u'e^(4x) + 16ue^(4x)
Using these,
y2'' - 8y2' + 16y2 =
[u''e^(4x) + 8u'e^(4x) + 16ue^(4x)] - 8[u'e^(4x) + 4ue^(4x)] + 16ue^(4x) = 0
u''e^(4x) = 0
Let w = u', then w' = u''
w'e^(4x) = 0
w' = 0
Integrating this, we have
w = C1
But w = u'
u' = C1
Integrating again, we have
u = C1x
But y2 = ue^(4x)
y2 = C1xe^(4x)
And this is the second solution