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iogann1982 [59]
2 years ago
4

Which of the following points is NOT a solution of the inequality y> [x] + 3

Mathematics
2 answers:
MAVERICK [17]2 years ago
7 0
A. -3, 0 is the correct answer.<span />
Misha Larkins [42]2 years ago
7 0

Answer:

Option A) (-3,0)

Step-by-step explanation:

We are given an inequality:

y> [x] + 3

Here [x] is the greatest integer function and defined as:

  • ⌊x⌋=the largest integer that is less than or equal to x for all real values of x.

The attached image shows the graph for the given inequality.

A) (-3, 0)

y> [x] + 3\\0 > [-3] + 3\\0 > 0

which is not true.

B) (-3, 6)

y> [x] + 3\\6 > [-3] + 3\\6 > 0

which is true

C) (0, 4)

y> [x] + 3\\4 > [0] + 3\\4 > 3

Thus, (-3,0) is not a point in solution for given inequality.

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Mkey [24]

The x-intercept is a point on the x-axis.
y=0 at every point on the x-axis.

                                       -2x + 1/2(0) = 18

                                       -2x              =  18

Divide each side by  -2 :    x = -9

7 0
2 years ago
Nikki and Jonathan both solve this system of equations: y=−2.7x+3.2 y = - 2 . 7 x + 3 . 2 y=1.3x+1.6 y = 1 . 3 x + 1 . 6 Jonatha
N76 [4]

We have two equations that were solved by Nikki and Jonathon:

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  • y=1.3x+1.6

Equating the above two:

⇒ 1.3x + 1.6 = -2.7x + 3.2

⇒ 4x = 1.6

⇒ x = 0.4

Hence, substituting the value of x in one of the equations we get:

y = 1.3×0.4 + 1.6 = 2.12

So the solution is (0.4, 2.12)

Jonathon's solution was (0.4, 2.12) and Nikki's was (2.25, 0.5). Hence Jonathon gave the correct solution.

7 0
2 years ago
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True or False? A circle could be circumscribed about the quadrilateral below.
SVEN [57.7K]

Answer:

<em>The correct answer is:   False</em>

Step-by-step explanation:

<u>If the sum of the opposite angles in a quadrilateral is 180°</u>, then a circle can be circumscribed about the quadrilateral.

Here,  \angle B+\angle D= 110\°+90\° = 180\°

but,  \angle A+\angle C= 70\°+90\°= 160\°

So, a circle can't be circumscribed about the given quadrilateral.

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2 years ago
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2 years ago
The indicated function y1(x) is a solution of the given differential equation. Use reduction of order or formula (5) in Section
LUCKY_DIMON [66]

Answer:

y2 = C1xe^(4x)

Step-by-step explanation:

Given that y1 = e^(4x) is a solution to the differential equation

y'' - 8y' + 16y = 0

We want to find the second solution y2 of the equation using the method of reduction of order.

Let

y2 = uy1

Because y2 is a solution to the differential equation, it satisfies

y2'' - 8y2' + 16y2 = 0

y2 = ue^(4x)

y2' = u'e^(4x) + 4ue^(4x)

y2'' = u''e^(4x) + 4u'e^(4x) + 4u'e^(4x) + 16ue^(4x)

= u''e^(4x) + 8u'e^(4x) + 16ue^(4x)

Using these,

y2'' - 8y2' + 16y2 =

[u''e^(4x) + 8u'e^(4x) + 16ue^(4x)] - 8[u'e^(4x) + 4ue^(4x)] + 16ue^(4x) = 0

u''e^(4x) = 0

Let w = u', then w' = u''

w'e^(4x) = 0

w' = 0

Integrating this, we have

w = C1

But w = u'

u' = C1

Integrating again, we have

u = C1x

But y2 = ue^(4x)

y2 = C1xe^(4x)

And this is the second solution

5 0
2 years ago
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