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oksano4ka [1.4K]

2 years ago

5

Simon entered a number into his calculator. To this number, he added the square of the original number and the cube of the origi

nal number. Simon got the answer 543.192 Use a trial and improvement method to find the number that Simon first entered into his calculator.

1 answer:

densk [106]2 years ago

4 0

Answer:

7.8. First plug in a number, then just keep trying till you get 7.8

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Among 21- to 25-year-olds, 29% say they have driven while under the influence of alcohol. Suppose that three 21- to 25-year-olds

Vilka [71]

Answer:

0.6421

Step-by-step explanation:

In this case we have 3 trials and we have 2 options for each one. The driver has or hasn't been under alcohol influence. The probability that the driver has is 0.29 and the probabiility that the driver hasn't is 1 - 0.29 = 0.71

each trial is independent because we are assuming that the population of drivers in between 21 and 25 years old is very big.

The probability that one of them was under alcohol influence can be found by finding the probability that non of them was under alcohol influence because:

1 = p(x = 0) + p(x ≥ 1)

p(x ≥ 1) = 1 - p(0)

The probability that none of them was under alcohol influence is going to be:

0.71×0.71×0.71 = 0.3579

The probability of finding at least one driver that has been under alcohol influence is:

0.6421

4 0

2 years ago

Kamden is a mind-reading alien. He had each friend draw and look at a card, then he guessed whether the card had a star on it. T

torisob [31]

Answer: This is what Khan Academy said the answer was

7 0

2 years ago

Consider the product (x + y + z)2. If the expression is multiplied out and like terms collected, the result is: x2 + y2 + z2 + 2

VLD [36.1K]

Answer:

Part a: The coefficient of $v^9w^2x^5y^7z^2$ is $1.766 \times 10^{13}$

Part b: The number of terms are 23751.

Step-by-step explanation:

part a

From the given equation the

$(x+y+z)^2=x^2+y^2+z^2+2xy+2yz+2zx$

So the coefficient of any term $x^ny^nz^n$ is given as

$\dfrac{2!}{n!n!n!}$

Similarly for the generic equation of coefficient of the term $x_1^{r_1}x_2^{r_2}x_3^{r_3}......x_k^{r_k}$ in the equation of form $(x_1+x_2+x_3+x_4......x_k)^n$ is given as

$\dfrac{n!}{r_1!r_2!r_3!....r_k!}$

So now the coefficient of $v^9w^2x^5y^7z^2$ is given as

$=\dfrac{25!}{9!2!5!7!2!}\\=1.766 \times 10^{13}$

The coefficient of $v^9w^2x^5y^7z^2$ is $1.766 \times 10^{13}$

Part b:

The number of terms is given as $\left (\ {{m+n-1} \atop {n}} \right )$

where m is the number of variables which are 5 here

n is the power which is 25 so the number of variables is given as

$\left (\ {{5+25-1} \atop {25}} \right )\\\left (\ {{29} \atop {25}} \right )\\\dfrac{29!}{25!4!}=23751$

So the number of terms are 23751.

3 0

2 years ago

An object is thrown from a height of 5 in. After 2 s, the object reaches a maximum height of 9 in, and then it lands back on the

Marta_Voda [28]

Answer:

y=-(x-2)^2+9

Step-by-step explanation:

Hope this helps

7 0

2 years ago

Mike forgot to replace the cap on a bottle of room freshener. The room freshener began to evaporate at the rate of 15% per day.

aleksandrvk [35]

Given:
bottle of room freshener = 40 grams
evaporates at the rate of 15% per day.

f(x) = 40(.85)^x

x y
1 34
2 28.9
3 24.57
4 20.88
5 17.75

<span>graph of exponential function going down from left to right in quadrant 1 through the point 0, 40 and approaching the x axis</span>

8 0

2 years ago

Read 2 more answers