We are given here that a blackjack hand consists of:
1 of the 4 aces = 4 / 52
1 of the 16 cards worth 10 points (10, jack, queen, king)
= 16 / 52
So assuming that cards are dealt without replacement,
therefore the probability of getting a blackjack hand is:
<span>P = 1st is ace * 2nd is 10 pt card +
1st is 10 pt card * 2nd is ace</span>
P = (4 / 52) * (16 / 51) + (16 / 52) * (4 / 51)
P = 0.04827 = 4.83%
Therefore there is a 4.83% probability to get a blackjack
hand.
<span> </span>
For a 30-60-90 triangle the sides always have the same relationship
Short leg = a
Long leg = a√3
Hypotenuse = 2a
BC is the short leg of ∆ABC
Given BC = 2
BC = a
Therefor
a = 2
AB = 2a = 4
AC = a√3 = 2√3
For ∆ACD
As above AC = 2√3
Since AC is the hypotenuse of ∆ACD
2a = 2√3
a = √3
CD = a = √3
AD = a√3 = 3
For ∆BCD
As above
BC = 2
CD = √3
Since BC is the hypotenuse of ∆BCD
2a = 2
a = 1
DB = a = 1
Answer:
Step-by-step explanation:
15.97
Answer:
1/9; 4/9; 1/12; 1/6
Step-by-step explanation:
the probability that both numbers are greater than 6 if the same number can be chosen twice--> 3/9 * 3/9 = 1/9
the probability that both numbers are less than 7 if the same number can be chosen twice --> 6/9 * 6/9 = 4/9
the probability that both numbers are odd numbers less than 6 if the same numbers cannot be chosen twice --> 3/9 * 2/8 = 1/12
the probability that both numbers are even numbers if the same numbers cannot be chosen twice --> 4/9 * 3/8 = 1/6
