Ask question

Ask question

All categories

Yakvenalex [24]

2 years ago

8

a warehouse store sells 5.5-ounce cans of tuna in packages of 6. a package of 6 cans costs $9.24. the store also sells 6.5-ounce

cams of the same tuna in packages of 3 cans for $4.68. it also sells 3.5-ounce cans in packages of 4 cans for $4.48. which package has the lowest cost per ounce of tuna?

2 answers:

Allushta [10]2 years ago

6 0

9.24 / (5.5 * 6) = 9.24 / 33 = 0.28 per oz

4.68 / (6.5 * 3) = 4.68 / 19.5 = 0.24 per oz

4.48 / (3.5 * 4) = 4.48 / 14 = 0.32 per oz

so the lowest cost is the 6.5 oz tuna in packs of 3 cans for 4.68

liberstina [14]2 years ago

5 0

Answer:

Second package costs the lowest.

Step-by-step explanation:

A ware house sells tuna cans weighing = 5.5 ounce

It sells the cans of tuna in the package of 6.

Weight of 6 cans = 5.5×6 ounce

Cost of the 6 cans = $9.24

Therefore, cost of 1 tuna can = $\frac{9.24}{5.5\times 6}=0.28$ per oz

Now weight of second type of tuna can = 6.5 ounce

Weight of 3 cans = 3×6.5 = 19.5 ounce

Cost of 3 tuna cans = $4.68

Cost of 1 tuna can = $\frac{4.68}{19.5}$

= $0.24 per oz.

Similarly cost of third type of tuna can = $\frac{4.48}{4\times 3.5}$

= $0.32 per oz

Second package has the lowest cost per ounce of tuna.

You might be interested in

The cost of hiring a surfboard involves an up-front fee plus an hourly rate. Three hours of hire costs $50 and 7 hours costs $90

siniylev [52]

Answer:

...... . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .

6 0

2 years ago

In a factory, two thirds of the floor are is taken up by the production line.Out of the remaining floor area,three fifths is tak

KATRIN_1 [288]

Answer:the floor area of the production line is 20000 m^2

Step-by-step explanation:

Let x represent the total area of the factory.

In the factory, two thirds of the floor are is taken up by the production line. This means that the area of the production line is 2/3 × x = 2x/3 m^2

The remaining floor area would be

x - 2x/3 = x/3 m^2

Out of the remaining floor area,three fifths is taken up by the office space. This means that the area taken up by the office space would be 3/5 × x/3 = x/5 m^2

The remaining area would be

x/3 - x/5 = 2x/15

The rest is warehouse space. The warehouse space occupies 2000m2. This means that

2x/15 = 2000

2x = 15 × 2000 = 30000

x = 30000/2 = 15000m^2

The floor area of the production line would be

(2 × 30000)/3 = 20000 m^2

8 0

2 years ago

Find the partial derivatives indicated Assume the variables are restricted to a domain on which the function is defined. z=x8+3y

ahrayia [7]

Answer:

Step-by-step explanation:

The question is incomplete. Here is the complete question.

Find the partial derivatives indicated Assume the variables are restricted to a domain on which the function is defined. z= $x^{8}$ + $3^{y}$ + $x^{y}$

a) Zx b) Zy

In differentiation, if y = axⁿ, y' = $nax^{n-1} \ where \ n\ is\ a\ constant$ . Applying this in question;

Given the function z = x⁸+ $3^{y}$ + $x^{y}$

$Z_x = \frac{\delta z}{\delta x} = 8x^{7} + 0 + yx^{y-1} \\\frac{\delta z}{\delta x} = 8x^{7} + yx^{y-1} \\$

Note that y is treated as a constant since we are to differentiate only with respect to x.

For Zy;

$Z_y = \frac{\delta z}{\delta y} =0+ 3^{y} ln3 + x^{y}lnx \\\frac{\delta z}{\delta y} = 3^{y} ln3 + x^{y}lnx } \\$

Here x is treated as a constant and differential of a constant is zero.

6 0

2 years ago

consider these graphs: Eric thinks the equation y=(x-3)^2 will match the blue graph. Jenney thinks it will match the red graph.

Dimas [21]

Answer: Jenny

Step-by-step explanation:

By subtitue Y = 0

0=(x-3)^2

And you get 3

3 0

2 years ago

F(x)=3x 2 +9f, left parenthesis, x, right parenthesis, equals, 3, x, squared, plus, 9 and g(x)=\dfrac{1}{3}x^2-9g(x)= 3 1 x 2

34kurt

Answer:

$f(g(x)) = \frac{1}{3}x^4 - 18x^2 + 252$

$g(f(x)) = 3x^4 + 18x^2 + 18$

<em>f(x) and g(x) and not inverse functions</em>

Step-by-step explanation:

Given

$f(x) = 3x^2 + 9$

$g(x) = \dfrac{1}{3}x^2 - 9$

Required

Determine f(g(x))

Determine g(f(x))

Determine if both functions are inverse:

Calculating f(g(x))

$f(x) = 3x^2 + 9$

$f(g(x)) = 3(\frac{1}{3}x^2 - 9)^2 + 9$

$f(g(x)) = 3(\frac{1}{3}x^2 - 9)(\frac{1}{3}x^2 - 9) + 9$

Expand Brackets

$f(g(x)) = (x^2 - 27)(\frac{1}{3}x^2 - 9) + 9$

$f(g(x)) = x^2(\frac{1}{3}x^2 - 9) - 27(\frac{1}{3}x^2 - 9) + 9$

$f(g(x)) = \frac{1}{3}x^4 - 9x^2 - 9x^2 + 243 + 9$

$f(g(x)) = \frac{1}{3}x^4 - 18x^2 + 252$

Calculating g(f(x))

$g(x) = \dfrac{1}{3}x^2 - 9$

$g(f(x)) = \frac{1}{3}(3x^2 + 9)^2 - 9$

$g(f(x)) = \frac{1}{3}(3x^2 + 9)(3x^2 + 9) - 9$

$g(f(x)) = (x^2 + 3)(3x^2 + 9) - 9$

Expand Brackets

$g(f(x)) = x^2(3x^2 + 9) + 3(3x^2 + 9) - 9$

$g(f(x)) = 3x^4 + 9x^2 + 9x^2 + 27 - 9$

$g(f(x)) = 3x^4 + 18x^2 + 18$

Checking for inverse functions

$f(x) = 3x^2 + 9$

Represent f(x) with y

$y = 3x^2 + 9$

Swap positions of x and y

$x = 3y^2 + 9$

Subtract 9 from both sides

$x - 9 = 3y^2 + 9 - 9$

$x - 9 = 3y^2$

$3y^2 = x - 9$

Divide through by 3

$\frac{3y^2}{3} = \frac{x}{3} - \frac{9}{3}$

$y^2 = \frac{x}{3} - 3$

Take square root of both sides

$\sqrt{y^2} = \sqrt{\frac{x}{3} - 3}$

$y = \sqrt{\frac{x}{3} - 3}$

Represent y with g(x)

$g(x) = \sqrt{\frac{x}{3} - 3}$

Note that the resulting value of g(x) is not the same as $g(x) = \dfrac{1}{3}x^2 - 9$

<em>Hence, f(x) and g(x) and not inverse functions</em>

4 0

2 years ago