Answer
Find out the m∠p .
To prove
As in ΔDAB is a right triangle
Apply pythagorean theorem
Hypotenuse ² = Perpendicular ² + Base²
DB² = AB² + AD²
AB = 5 units
AD = 6 units
Put in the above formula
DB² = 5² + 6²
= 25 + 36
= 61

= 7.8 units (approx)
Now in ΔDCB is a right triangle .
By using the trignometric identity .


As DC = 4 units
DB = 7.8 units (approx)
Put all the values in the trignometric identity .


∠p = 59.15 ° (approx)
The answer to the question is a
Answer:
i think you have written wrong equation
Step-by-step explanation:
Answer:
- arc BF = 76°
- ∠M = 31°
- ∠BGE = 121°
- ∠MFB = 111°
Step-by-step explanation:
(a) ∠FBM is the complement of ∠FBC, so is ...
∠FBM = 90° -52° = 38°
The measure of arc BF is twice this angle, so is ...
arc BF = 2∠FBM = 2(38°)
arc BF = 76°
__
(b) ∠M is half the difference between the measures of arcs BE and BF, so is ...
∠M = (1/2)(138° -76°) = 62°/2
∠M = 31°
__
(c) arc FC is the supplement to arc BF, so has measure ...
arc FC = 180° -arc BF = 180° -76° = 104°
∠BGE is half the sum of arcs BE and FC, so is ...
∠BGE = (1/2)(arc BE +arc FC) = (138° +104°)/2
∠BGE = 121°
__
(d) ∠MFB is the remaining angle in ∆MFB, so has measure ...
∠MFB = 180° -∠M -∠FBM = 180° -31° -38°
∠MFB = 111°