I solve this question by hand and have attached images for you because it is very difficult or impossible to do it here . I do it as simple as I can and make it very comprehensive for you. Hopefully, you will understand.
Note: the order for images remain same as I have attached.
The length of the GH segment is 13
Step-by-step explanation:
For solving this problem we need to remember some of the circle corollaries-
When two-chord intersects each other, the product of the chord segments are equal
The above corollary can be easily understood by looking at a diagram attached below-
In the figure, EF and GH are two chords intersecting at K
Thus, EK*KF= GK*KH
Values of the EK, KF, GK are given as 5, 6 and 3 respectively
Substituting the values we get
5*6=3*KH
KH= 10
We know that GH= GK+KH
Thus GH= 3+10= 13
We are usually concerned with one reaction. That is, the production of one specific set of products from a specific set of reactants.
The number of values of c/d would be the number of possible ways that a and b could recombine to form different pairs of products c and d. (You might get different reactions at different temperatures, for example. Or, you might get different pars of ions.)
Usually, the number of values of c/d is one (1). (Of course, if you simply swap what you're calling "c" and "d", then you double that number, whatever it is.)
Answer:
4
Step-by-step explanation:
6-4+2*5=12
12/3
4
<span>Graphing calculators are more accurate and are faster when finding the solution(s). <span>When solving a system of equations with a graphing calculator, you can have the calculator graph equations of any degree and shape. The graphing calculator also has functions to find where the graphs intersect between two points and are accurate sometimes to ten decimal places. When compared to graphing by hand you can get inaccurate results and results that are not as precise.</span></span>