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mars1129 [50]
2 years ago
10

Every five years in march, the population of a certain town is recorded. In 1995,the town had a population of 4,500 people. From

1995 to 200, the population increased by 15%. From 2000 to 2005,the population decrease d by 4%. What was the town's population in 2005?
Mathematics
1 answer:
Mumz [18]2 years ago
6 0
<span>From 2000 to 2005,the population decrease d by 4%. What was the town's population in 2005?
The first thing we want to look at is that from 1995 to 2000, the population increased by 15% (from 4,500.) So that means we multiply 4,500 times 15% to get 15% of 4,500.
.15*4,500=675 (.15 is the same thing as 15%)
So we see it increased by 675.
4,500+675=5175
So in 2000, there were 5,175 people
So now we do the same thing for 2000 to 2005. 
The population has decreased by 4% (or .04)
Now to see what 4% of 5,175 is we multiply is by 4% 
.04*5175=207
So now if it has decreased by 207 (4% of the population in 2000)
Now we subtract that number from the population in 2000
5175-207=4968
In 2005 there are 4968 people.

</span>
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Answer:

You'd be 2 * 10^{-6} times tall

Step-by-step explanation:

Given

Represent the previous and new diameter by D1 and D2;

D_1 = 2 * 10^{-8}m

D_2 = 1\ cm

To determine how tall you'd be, we need to divide D2 by D1;

Ratio = \frac{D_2}{D_1}

Substitute values for D2 and D1

Ratio = \frac{2 * 10^{-8}m}{1\ cm}

Convert cm to m

Ratio = \frac{2 * 10^{-8}m}{1 * 0.01\ m}

Ratio = \frac{2 * 10^{-8}m}{0.01\ m}

Convert denominator to exponents

Ratio = \frac{2 * 10^{-8}m}{10^{-2}\ m}

Ratio = \frac{2 * 10^{-8}}{10^{-2}}

Apply Law of indices

Ratio = 2 * 10^{-8} * 10^2

Ratio = 2 * 10^{-8+2}

Ratio = 2 * 10^{-6}

Hence;

<em>You'd be </em>2 * 10^{-6}<em> times tall</em>

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Answer:

(a) P(B) = 0.008, (b) P(A∩B) = 0, (c) Yes, A and B are mutually exclusive events, (d) P(A∪B)=0.948, (e) 0.948, (f) 0.06

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We have three different posibilities

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(f) The probability that the machine either overfill or underfills is

P(C∪B)=P(C)+P(B)=0.052+0.008=0.06 because C and B are mutually exclusive events.

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