Question

9. The average diameter of an atom is 2 x 10-8 m. What if the average diameter of an atom was 1 cm? How tall would you be?

Answer 1

Answer:

You'd be $2 * 10^{-6}$ times tall

Step-by-step explanation:

Given

Represent the previous and new diameter by D1 and D2;

$D_1 = 2 * 10^{-8}m$

$D_2 = 1\ cm$

To determine how tall you'd be, we need to divide D2 by D1;

$Ratio = \frac{D_2}{D_1}$

Substitute values for D2 and D1

$Ratio = \frac{2 * 10^{-8}m}{1\ cm}$

Convert cm to m

$Ratio = \frac{2 * 10^{-8}m}{1 * 0.01\ m}$

$Ratio = \frac{2 * 10^{-8}m}{0.01\ m}$

Convert denominator to exponents

$Ratio = \frac{2 * 10^{-8}m}{10^{-2}\ m}$

$Ratio = \frac{2 * 10^{-8}}{10^{-2}}$

Apply Law of indices

$Ratio = 2 * 10^{-8} * 10^2$

$Ratio = 2 * 10^{-8+2}$

$Ratio = 2 * 10^{-6}$

Hence;

You'd be $2 * 10^{-6}$ times tall