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2 years ago

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Nina is 10 years younger than Deepak. Deepak is 3 times as old an Nina. Which system of equations can be used to find d, Deepak’

s age, and n, Nina’s age?

1 answer:

nevsk [136]2 years ago

3 0

The answer would be the first choice which is d = n + 10, d = 3n. Deepak is 10 years older than Nina, so knowing this, the equation cancels out B and D. And Deepak is 3 times Nina's age, not Nina's age is three times Deepak's. It is not the other way around.

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A baby otter was born 3/4 of a month early. At birth it's weight was 7/8 kilograms which is 9/10 kilogram less than the average

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Answer:

The average weight of new born otter was, $1\frac{31}{40}$

Step-by-step explanation:

Let average weight of new born otter be x.

As per the given statement: At birth it's weight was 7/8 kilograms which is 9/10 kilogram less than the average weight of a new born otter in the aquarium

" $\frac{9}{10}$ kg less than average weight of a new born otter" means $x-\frac{9}{10}$

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We need a sample size of at least 719

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Now, we have to find z in the Ztable as such z has a pvalue of $1-\alpha$ .

So it is z with a pvalue of $1-0.025 = 0.975$ , so $z = 1.96$

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In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

How large a sample size is required to vary population mean within 0.30 seat of the sample mean with 95% confidence interval?

This is at least n, in which n is found when $M = 0.3, \sigma = 4.103$ . So

$M = z*\frac{\sigma}{\sqrt{n}}$

$0.3 = 1.96*\frac{4.103}{\sqrt{n}}$

$0.3\sqrt{n} = 1.96*4.103$

$\sqrt{n} = \frac{1.96*4.103}{0.3}$

$(\sqrt{n})^{2} = (\frac{1.96*4.103}{0.3})^{2}$

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2 years ago

What is the simplest form of RootIndex 3 StartRoot 27 a cubed b Superscript 7 Baseline EndRoot?

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Answer: $3ab\sqrt[3]{b^4}$

Step-by-step explanation:

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$(a^m)(a^n)=a^{(m+n)$

Then, you can rewrite the expression as following:

$=\sqrt[3]{27a^3b^4b^3}$

The next step is to descompose 27 into its prime factors:

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Now you must substitute $3^3$ inside the given root. Then:

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