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n200080 [17]
2 years ago
7

Which equation is equivalent to the given equation? - 4(x – 5) + 8x = 9x – 3

Mathematics
2 answers:
Rama09 [41]2 years ago
4 0

Answer:

B

Step-by-step explanation:

-4x +20 +8x = 9x -3. That's equall to 4x+20=9x-3. subtract 9x both sides, -5x+20=-3. subtract 20 both sides, -5x=-23.

seraphim [82]2 years ago
3 0

Hi!

-4(x - 5) + 8x = 9x - 3

-4x + 20 + 8x = 9x - 3

-4x + 8x - 9x = -3 - 20

<u>-5x = -23</u>

Answer: B

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Graph the linear equation. Find three points that solve the equation, then plot on the graph. -3y=x-6
nata0808 [166]

Answer:

Step-by-step explanation:                               x - 6

The given equation can be re-written as y = ---------                              

                                                                             -3

Arbitrarily choose x = 0.  Then:

      x - 6         0-6

y = --------- = ----------- = 2, so (0, 2) is a point on the graph which is also the                              

          -3            -3                                                                  y-intercept

Arbitrarily choose x = 6.  Then y = 0, and (6, 0) is another point on the graph                                    

                                                              which happens to be the x-intercept

arbitrarily choose x = 12.  Then y = (12 - 6) / (-3) = -2.  Then  (12, -2) is            

                                                                                  another point on the

                                                                                  graph.

Plot (12, -2), (6, 0) and (0, 2).  Draw a line through these three points.

6 0
2 years ago
Complete the steps in solving the quadratic function 7x – 9 = 7x2 – 49x by completing the square. –9 = 7x2 – x –9 + = 7(x2 – 8x
anzhelika [568]

Answer:

A) 56 . . . . . . the (negative) sum of -7 and -49

b) 112 . . . . . the product of 7 and 16

c) 16 . . . . . . the square of 8/2

8 0
2 years ago
Read 2 more answers
The first-, second-, and third-year enrollment values for a technical school are shown in the table below.
VARVARA [1.3K]

Answer:

The solution to f(x) = t(x) is x = 2010

Option 3 is true.

Step-by-step explanation:

The first-year , second-year , and third-year enrollment values for a technical school are shown in the table below.

Year (x)      First Year f(x)      Second Year s(x)       Third Year t(x)

 2009              785                        756                           756

 2010               740                        785                           740

 2011                690                        710                            781

 2012               732                        732                            710

 2013                781                        755                            800

Now we will check each option.

Option 1: The solution to f(x) = s(x) is x = 2,009

In year 2009, f(x)=s(x)

But 785≠756

Thus, False

Option 2: The solution to f(x) = s(x) is x = 785

x represents year, but 785 it no year

Thus, False

Option 3: The solution to f(x) = t(x) is x = 2010

In year 2010, f(x)=t(x)=740

But 740=740

Thus, True

Option 4: The solution to f(x) = t(x) is x =740

x represents year, but 740 it no year

Thus, False

8 0
2 years ago
Food allergies affect an estimated 7% of children under age 5 in the US. What is the probability that in a kindergarden class of
bezimeni [28]

Answer:

Probability of atleast one of 12 student has food allergies ≈ 0.58 ( approx)

Step-by-step explanation:

Given: Probability of a children under age 5 has food allergies = 7%

                                                                                                        =\frac{7}{100}

To find : Probability of atleast one of 12 student has food allergies

Probability of a chindren under age 5 does not have food allergies = 1-\frac{7}{100}

                  ⇒ prob = \frac{93}{100}

now we find Probability of atleast one of 12 student has food allergies this means we have to find prob of 1 student, 2 student, 3 student, till 12 student have allergy out of 12 student of class then add all prob.

But instead of finding all these probability we find probability of student having no allergy.i.e., 0 student then subtract it from 1(total probability)

Probability of 0 student having allergy out of 12 student = (\frac{93}{100})^{12}

Therefore, Probability of atleast one of 12 student has food allergies

                  = 1-(\frac{93}{100})^{12}

                  = 0.581403702521

                  ≈ 0.58 ( approx)

                 

8 0
2 years ago
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After the bank cashed a check Maureen wrote for $60, her balance was -$14.The equation b+(-60)=-14 can be used to represent this
dem82 [27]

we are given

b+(-60)=-14

Since, we have to solve for b

b-60=-14

so, we will isolate b ony one side

so, we will add 60 on both sides

b-60+60=-14+60

b=-14+60

b=46

so,

Answer:

Maureen should have added 60 to both sides.

5 0
2 years ago
Read 2 more answers
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