Answer:
0.025
Step-by-step explanation:
-This is a conditional probability problem.
-Let L denote lens defect and C charging defect.
#We first calculate the probability of a camera having a lens defect;

#Calculate the probability of a camera having a charging defect:

The the probability that a camera has a lens defect given that it has a charging defect is calculated as:

Hence, the probability that a camera has a lens defect given that it has a charging defect is 0.025
Recall that:
sin(A + B) = sinAcosB + cosAsinB
Therefore:
sin11°cos19° + cos11°sin19° = sin(11° + 19°)
= sin30° = 0.5
I hope this explains it.
Answer:
The probability that a defective rod can be salvaged = 0.50
Step-by-step explanation:
Given that:
A machine shop produces heavy duty high endurance 20-inch rods
On occasion, the machine malfunctions and produces a groove or a chisel cut mark somewhere on the rod.
If such defective rods can be cut so that there is at least 15 consecutive inches without a groove.
Then; The defective rod can be salvaged if the groove lies on the rod between 0 and 5 inches i.e ( 20 - 15 )inches
Now:
P(X ≤ 5) = 
= 0.25
P(X ≥ 15) = 
= 0.25
The probability that a defective rod can be salvaged = P(X ≤ 5) + P(X ≥ 15)
= 0.25+0.25
= 0.50
∴ The probability that a defective rod can be salvaged = 0.50
Answer:
<em>5,598 cans are required to empty the vessel</em>
Step-by-step explanation:
The volume of a cylinder of radius r and height h is:

The volume of a box of dimensions X, Y, and Z is:
V=X.Y.Z
A cylinder of r=1.4 m and height h=1.5 is used to store vegetable ghee. It contains a volume of:


Converting to cubic cm:


The volume of each rectangular tin can is:


The number of cans required to empty the vessel is:

5,598 cans are required to empty the vessel