Answer: On average, the weight of a pet visiting this vet on this day is about 2.4 pounds away from 12.9 pounds.
If the MAD of weights for another day was 1.5, then that day's weights would be less variable than the weights of pets seen on this day.
Step-by-step explanation:
Given: The measures in the table describe the weights of animals that visited a vet on one day, in pounds.
Mean = 12.9
Median= 12.0
Mode = 12.0
Mean Absolute Deviation = 2.4
We know that the mean absolute deviation (MAD) of a data set is the mean distance between each and every data value and the mean.It tells about the variation in a data set.
Therefore, On average, the weight of a pet visiting this vet on this day is about 2.4 pounds away from 12.9 pounds.
Also, If the MAD of weights for another day was 1.5, and since 1.5< 2.4.
Then that day's weights would be less variable than the weights of pets seen on this day.
Answer:
Length: 80 feet
Width: 36 feet
Step-by-step explanation:
232/2 = 116
116-36 = 80
(i.e. 80+80+36+36=232)
There are 3 choices for the bottom scoop. Then there are only 3 choices for the scoop above that (since one flavor has already been used), then 2 choices for the next scoop, and 1 choice for the final scoop. This gives a total of 18 <span>possible cones.
Hope this helps.
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