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alisha [4.7K]
2 years ago
13

Why is it important to use standard english when applying for a job

Computers and Technology
2 answers:
algol132 years ago
8 0
To start of on the right foot with your boss by showing him/her that you can be professional, but not be intimidating. Hope this helped.
maria [59]2 years ago
8 0

Answer:

Show profesionalism

Explanation:

If you talk in an standar english, not using modisms or regionalisms you can show to however is going to be in charge of hiring you that you can moderate yourself and that you are someone that can behave in different situations, this can help you get the job, showing profesionalism is something that many employers want from their employees and that ability to speak formally and profressionally can show a lot of that.

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Which of the following is a benefit, as well as a risk, associated with client/server networks?
KATRIN_1 [288]
C would be the correct answer to this question
6 0
2 years ago
Rootkits are kernel programs having the ability to hide themselves and cover up traces of activities. It replaces certain operat
yawa3891 [41]

Answer:

Boot loader level rootkit

Explanation:

A rootkit is a malicious program which is used by hackers to gain illegal access to the computer system.A bootloader level rootkit also known as bootkit, infects the master boot record(MBR) of the hard drive.As a result bootloader level rootkit is able to compromise the boot process and can modify the boot sequence of the machine to load themselves instead of the original virtual machine monitor or operating system.

3 0
2 years ago
Create the class named SortFile. The class will have a single attribute, which is an ArrayList of integers. The class will have
S_A_V [24]

Answer:

See explaination

Explanation:

//SortFile.java

import java.io.File;

import java.io.FileNotFoundException;

import java.util.ArrayList;

import java.util.Arrays;

import java.util.Scanner;

public class SortFile {

// array list of integers to store the numbers

private ArrayList<Integer> list;

// default constructor

public SortFile() {

// initializing list

list = new ArrayList<Integer>();

// reading file name using a scanner

Scanner sc = new Scanner(System.in);

System.out.print("Enter file name: ");

String filename = sc.nextLine();

// opening file inside a try catch block. if you want to throw exception

// instead, just remove try-catch block and add throws

// FileNotFoundException to the method signature.

try {

// opening file

sc = new Scanner(new File(filename));

// looping and reading each integer from file to list

while (sc.hasNextInt()) {

list.add(sc.nextInt());

}

// closing file

sc.close();

} catch (FileNotFoundException e) {

// exception occurred.

System.err.println(e);

}

}

// constructor taking a file name

public SortFile(String filename) {

// initializing list

list = new ArrayList<Integer>();

// opening file inside a try catch block. if you want to throw exception

// instead, just remove try-catch block and add throws

// FileNotFoundException to the method signature.

try {

Scanner sc = new Scanner(new File(filename));

// looping and reading each integer from file to list

while (sc.hasNextInt()) {

list.add(sc.nextInt());

}

sc.close();

} catch (FileNotFoundException e) {

System.err.println(e);

}

}

// method to return a sorted array of integers containing unique elements

// from list

public int[] sort() {

// creating an array of list.size() size

int arr[] = new int[list.size()];

// count of unique (non duplicate) numbers

int count = 0;

// looping through the list

for (int i = 0; i < list.size(); i++) {

// fetching element

int element = list.get(i);

// if this element does not appear before on list, adding to arr at

// index=count and incrementing count

if (!list.subList(0, i).contains(element)) {

arr[count++] = element;

}

}

// now reducing the size of arr to count, so that there are no blank

// locations

arr = Arrays.copyOf(arr, count);

// using selection sort algorithm to sort the array

int index = 0;

// loops until index is equal to the array length. i.e the whole array

// is sorted

while (index < arr.length) {

// finding the index of biggest element in unsorted array

// initially assuming index as the index of biggest element

int index_max = index;

// looping through the unsorted part of array

for (int i = index + 1; i < arr.length; i++) {

// if current element is bigger than element at index_max,

// updating index_max

if (arr[i] > arr[index_max]) {

index_max = i;

}

}

// now we simply swap elements at index_max and index

int temp = arr[index_max];

arr[index_max] = arr[index];

arr[index] = temp;

// updating index

index++;

// now elements from 0 to index-1 are sorted. this will continue

// until whole array is sorted

}

//returning sorted array

return arr;

}

//code for test-run

public static void main(String[] args) {

//initializing SortFile using default constructor

SortFile sortFile = new SortFile();

//displaying sorted array

System.out.println(Arrays.toString(sortFile.sort()));

}

6 0
2 years ago
Assume we have a computer where the clocks per instruction (CPI) is 1.0 when all memory accesses hit in the cache. The only data
umka21 [38]

Answer:

6.6 times faster considering I-cache

Explanation:

<em>Given data </em>:

CPI  = 1

Data accesses ( loads and stores ) = 40% of instructions

Miss penalty = 200 clock cycles

Miss rate = 2% for I-cache ,  5% for D-cache

<u>Determine how much faster the computer will be if all instructions were Cache hits </u>

In this condition the memory stall = 0

hence: CPU ideal time = ( Ic * CP1  + memory stall ) * clock cycle time --- ( 1 )

                                     = ( Ic * 1 + 0 ) * clock cycle time

<em>Note : Memory stall = Ic * ( 1 + load fraction ) * miss rate * miss penalty  --- ( 2)</em>

back to equation 1

Memory stall ( for I-cache ) = Ic * ( 1 + 40% ) * 2% * 200

                                              = 5.6 Ic

Input value into equation 1

CPU ideal time = Ic * 1 + 5.6Ic * clock cycle time

                         = ( 6.6 Ic ) * clock cycle time

To determine how much faster we take the ratio of the CPU ideal time

=   6.6 Ic * clock cycle time / 1  Ic * clock cycle time

= 6.6 times faster

4 0
2 years ago
A business wants to centralize its administrative tasks. At the same time, it wants the existing systems to manage and sustain t
Irina18 [472]
Documentation and time management
7 0
2 years ago
Read 2 more answers
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