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mixer [17]
2 years ago
9

What is the overall purpose of​ differentiation?

Business
1 answer:
Roman55 [17]2 years ago
8 0
The overall purpose of differentiation is letter e, to create superior customer value. It is because differentiation is being defined as a way of making products to be more appealing or attractive in means of using unique qualities that may be of the customer's taste in a way of creating customer value.
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Help Please!!!!Jamir has decided that he needs a new car. He has found the model and color he wants for a purchase price of $25,
Leokris [45]

Answer:

He will have to come up with a bigger down payment

His monthly payments will be higher.

If Jamir leases the car, his down payment will be $1500.

If he purchases the car, his down payment will be 10% of purchase price which will be \frac{10}{100} *25,838 = $2583.80.

Hence his down payment will be higher if he purchases the car.

If Jamir leases the car, his monthly payments will be $290, as against the monthly payment of $432.46, which is higher.

0 0
2 years ago
Read 2 more answers
Emily, who is single, has been offered a position as a city landscape consultant. The position pays $153,800 in cash wages. Assu
Law Incorporation [45]

Answer:

a) using the 2020 tax schedule:

Emily's taxable income = $153,800 - $12,200 = $141,600

Emily's tax liability = $14,605.50 + [($141,600 - $85,525) x 24%] = $28,063.50

Emily's after tax compensation = $153,800 - $28,063.50 = $125,736.50

b and c ) if Emily (or Rick?) get a $102,500 offer that includes benefits worth $4,900 that are not taxable:

taxable income = $102,500 - $12,200 = $90,300

tax liability = $14,605.50 + [($90,300 - $85,525) x 24%] = $15,751.50

after tax compensation = $102,500 - $15,751.50 + $4,900 = $91,648.50

5 0
2 years ago
Wells Technical Institute (WTI), a school owned by Tristana Wells, provides training to individuals who pay tuition directly to
Anna35 [415]

Answer:

Given below

Explanation:

<u><em>Wells Technical Institute (WTI)</em></u>

<u><em>General Journal</em></u>

<u><em>31st December Journal Entries</em></u>

Insurance Expense $2,542  Dr

Prepaid Insurance $2,542  Cr

  • Insurance expired on Dec 31st

Inventory Account  $2,204  Dr

Prepaid Supplies  Account $2,204 Cr

<em>The prepaid supplies is closed to inventory account and inventory account is closed to Income summary account.</em>

Income Summary Account  $2,204  Dr

Inventory Account  $2,204  Cr

<em>But if only adjusting entry is required not closing inventory  then </em>

Prepaid Supplies  Account $2,204 Dr

Inventory Account  $2,204  Cr

<em>Inventory account is adjusted with the Prepaid Supplies .</em>

  • An inventory count shows that teaching supplies costing $2,204 are available at year-end.

Depreciation Expense Equipment $10,170Dr

Accumulated Depreciation Equipment $10,170 Cr.

Depreciation Expense Library $5,085 Dr

Accumulated Depreciation Library  $5,085 Cr.

  • Annual depreciation on the equipment is $10,170. Annual depreciation on the professional library is $5,085.

Unearned Training Fees $ 4800 Dr

Training Fees Earned $ 4800 Cr

  • Fees for two course ( 2400*2= 4800) Earned.

Accounts Receivable Training Fees $6,498 Dr

Training Fees Earned $ $6,498  Cr

  • On October 15, WTI agreed to teach a four-month class (beginning immediately) for an executive with payment due at the end of the class. At December 31, $6,498 of the tuition has been earned by WTI.

Salaries Expense $ 400 Dr.

Salaries Payable $ 400 Cr.

Salaries  for two employees ( 2* 2* 100= 400)  for 2 days.

  • WTI's two employees are paid weekly. As of the end of the year, two days' salaries have accrued at the rate of $100 per day for each employee. The balance in the Prepaid Rent account represents rent for December.
6 0
2 years ago
Suppose the daily change in price of a stock is normally distributed with mean = .20 and standard deviation = .30. What price ch
uranmaximum [27]

Answer:

a=0.2 -0.674*0.3=-0.00235

So the value that separates the bottom 25% of data from the top 75% is -0.00235.  

Explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the variable of interest of a population, and for this case we know the distribution for X is given by:

X \sim N(0.2,0.3)  

Where \mu=0.2 and \sigma=0.3

For this part we want to find a value a, such that we satisfy this condition:

P(X>a)=0.75   (a)

P(X   (b)

Both conditions are equivalent on this case. We can use the z score again in order to find the value a.  

As we can see on the figure attached the z value that satisfy the condition with 0.25 of the area on the left and 0.75 of the area on the right it's z=-0.674. On this case P(Z<-0.674)=0.25 and P(z>-0.674)=0.75

If we use condition (b) from previous we have this:

P(X  

P(z

But we know which value of z satisfy the previous equation so then we can do this:

z=-0.674

And if we solve for a we got

a=0.2 -0.674*0.3=-0.00235

So the value that separates the bottom 25% of data from the top 75% is -0.00235.  

4 0
2 years ago
An artist who uses a spontaneous, less fussy approach to painting can be said to be using the ____________ technique
Scilla [17]
The technique that the artist is using could be described as the alla prima technique in which it is often used in paintings such as the oil paintings. It is a painting technique that uses wet paint to be able to give out its spontaneous and fuzzy look. The wet paints that are being applied to the portrait has many layers to show its structure or the beauty of the technique.
3 0
2 years ago
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