(99 PTS) NEED HELP FAST ILL MARK BRAINLIEST AND RATE 5 STARS AND SAY THANK YOU

the average hair skin and nails have a pH level of five generally falling between 4.5 and 6 true or false

Semmy [17]

The answer is true I’m pretty sure

7 0

2 years ago

Why might a lysosome fuse with or link up with a food vacuole

Tomtit [17]

Vacuoles store things, so it would make sense that food vacuoles store food. Lysosomes digest things into smaller usable materials (or destroy them) so lysosomes will attach to food vacuoles so they can efficiently digest food. The vacuole to store the food waiting to be digested by the lysosome. Hope this helped :)

8 0

2 years ago

Genetic linkage mapping for a large number of families identifies 4% recombination between the genes for Rh blood type and ellip

Cloud [144]

Answer:

0.2404

Explanation:

The genes R/r and E/e are linked and there is 4% recombination between them.

The possible genotypes and phenotypes are:

RR or Rr: Rh+ blood type
rr: Rh- blood type
EE or Ee: elliptocytosis
ee: normal red blood cells

Tom and Terri each have elliptocytosis (they are E_), and each is Rh+ (they are R_).

Tom's mother has elliptocytosis (E_) and is Rh- (rr), so she has the genotype Er/_r. His father is healthy (ee) and has Rh+ (R_), so he has the genotype eR/e_. Tom must have inherited his E allele from his mother and his R allele from his father, so he has the genotype eR/Er.

Terri's father is Rh+ (R_) and has elliptocytosis (E_), while Terri's mother is Rh- (rr) and is healthy (ee) with the genotype er/er. Terry could only receive the chromosome er from her mother, and because she is heterozygous for both genes the dominant alleles were both received from her father. Terri's genotype is ER/er.

The frequency of recombination is 4%, so 4% of the produced gametes will be recombinant. There are two possible recombinant gametes, so each will appear 2% of the times (a frequency of 0.02).

Tom will produce the following gametes:

eR, parental (0.48)
Er, parental (0.48)
er, recombinant (0.02)
ER (recombinant (0.02)

Terri will produce the following gametes:

ER, parental (0.48)
er, parental (0.48)
Er, recombinant (0.02)
eR, recombinant (0.02)

A child Rh- with elliptocytosis has the genotype rrE_. This can happen from the independent combination of the following gametes from Tom and Terri respectively:

Er (0.48) × er (0.48) = 0.2304 Er/er
Er (0.48) × Er (0.02) = 0.0096 Er/Er
er (0.02) × Er (0.02) = 0.0004 er/Er

And the total probability of having a rrE_ child will be 0.2304 + 0.0096 + 0.0004 = 0.2404

6 0

2 years ago

Demonstrate through chemical modeling what happens to the protein structure (keratin) of curly hair after a chemical relaxer and

NeX [460]

Answer:

Denaturation occurs.

Explanation:

When a chemical relaxer and heat applied to a curly hair, the protein present inside your hair get denature. Due to this denaturation of protein in the hair, the hair are soft and flexible which can be converted into any direction and different styles can be done. If chemical perm or relaxer is applied to straight hairs, it also denature the protein and make the hair curly.

8 0

2 years ago

The following figure shows a plant cell immediately after it has been placed in distilled water (A) and a plant cell that has be

DENIUS [597]

Answer:

Plant cell A has lower water potential than cell B. True

Plant cell B is isotonic to the fluid in the beaker. True

Plant cell B's water potential increased due to an increase in solutes inside the cell. False

Plant cell B is at equilibrium with the fluid in the beaker. True

Plant cell A has higher water potential than cell B. False

Plant cell A is at equilibrium with the fluid in beaker. False

Explanation:

Plant cell A has lower water potential than cell B. True

This statement is true because the water potential of A is -2 bars while that of B is zero bars.

Plant cell B is isotonic to the fluid in the beaker. = True

Isotonic solutions have equal water potential. Since the water potential of distilled water is zero and that of plant cell B is zero as well, plant cell B is isotonic to the fluid in the beaker.

Plant cell B's water potential increased due to an increase in solutes inside the cell = False.

An increase in solute inside the cell doe not increase water potential but rather reduces it.

Plant cell B is at equilibrium with the fluid in the beaker. = True

Plant cell B is at equilibrium with the fluid in the beaker because its water potential is zero since the negative solute potential is counterbalanced by the positive pressure potential.

Plant cell A has higher water potential than cell B = False.

Plant cell A has a lower water potential of -2 bars while plant cell B has a higher water potential of zero.

Plant cell A is at equilibrium with the fluid in beaker. = False.

Plant cell A is not at equilibrium with the fluid in the beaker, rather due to its negative water potential, water will move into the cell.

4 0

2 years ago