Answer:
Volume= 4 cm³
Density= 2 g/cm³
Explanation:
We have the following data:
volume= V= 8 cm³
mass= m= 16 g
The density is the mass per volume of a substance, so the density of the rock is:
density= d= 16 g/8 cm³= 2 g/cm³
When we cut the rock in half, we have a half volume and a half mass:
V= 8 cm³/2= 4 cm³
m= 16 g/2= 8 g
But the density is not altered because it is an intrisic property - it does not change with the amount of subtance. Thus, the density of a half rock is:
d = m/V= 8 g/4 cm³= 2 g/cm³
The answer to the first unknown in the problem is the "Areolar" while in the second unknown in the problem is the "Cartilage". Hence, to complete the given statement in the problem, we have an example of a high vascular tissue is "AREOLAR" tissue and as an example also of a tissue that is not highly vascular is the "CARTILAGE".
<span>The barn owl's right ear opens slightly upward while its left ear opens slightly downward. this difference enables the owl to detect the location of a sound. It would actually depend on the location of where it would be at, and based on this, depending where it would then be located, this would then be able to differentiate where it would be located.</span>