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harkovskaia [24]
2 years ago
3

The formula for the area A of a trapezoid is shown below where h represents its height and b1 and b2 represent the lengths of it

s bases. for this problem let b1 represent the length of its shorter base. A=1/2h (b1+b2) which of the descriptions below is equivalent to the formula shown above?
A.The length of the longer base is equal to the quotient of twice the area and the height plus the length of the shorter base.
B.The height is equal to twice the area divided by the productof the lengths of the two bases.
C.The length of the longer base is equal to the quotient of the area and the height, minus half the length of the shortee base
D.The height is equal to twice the area divided by the sum of the lengths of the two bases.

Mathematics
1 answer:
olga nikolaevna [1]2 years ago
3 0
A = ( 1 / 2 ) h ( b1 + b2 ) ;
h = ( 2A) / ( b1 + b2 );
b2 = ( 2A / h) - b1 ;

D. is the right answer ; 
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Zolol [24]
(a) If y(t) is the mass after t days and y(0) = A then y(t) = Ae^{kt}.

y(1) = Ae^k = 0.945A \implies e^k = 0.945 \implies k = \ln 0.945

\text{Then } Ae^{(\ln 0.945)t} = \frac{1}{2}A\ \Leftrightarrow\ \ln e^{(\ln 0.945)t} = \ln \frac{1}{2}\ \Leftrightarrow\  ( \ln 0.945) t = \ln \frac{1}{2} \Leftrightarrow \\ \\
t = - \frac{\ln 5}{\ln 0.945} \approx 12.25 \text{ years}

(b)
Ae^{(\ln 0.945) t} = 0.20 A \ \Leftrightarrow\ (\ln 0.945) t \ln \frac{1}{5}\ \implies \\ \\
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3 0
2 years ago
If -3y+5=-4 find the value of 5y
artcher [175]
-3y + 5 = -4   Subtract 5 from both sides
      -3y = -9   Divide both sides by -3
         y = 3

Now, plug that into 5y

 5y    Plug in 3
5(3)   Multiply
 15

5y = 15
6 0
2 years ago
Jude says that the volume of a square pyramid with base edges of 12 in and a height of 10 in is equal to the volume of a cylinde
Lapatulllka [165]

Answer:

No, not correct

Step-by-step explanation:

Square pyramid volume:  (1/3) (base area)(height).  In this case,

V = (1/3)*(12 in)^2*(10 in) = 480 in^3 = 480 in^3

Cylinder volume:  (base area)*(height).  In this case,

V = (3.14)*(6.77 in)^2*(10 in) = 452.12 in^3.

No, Jude is not correct; the 480 in^3 volume of the square pyramid is not the same as the 452.12 in^3 volume of the cylinder.

7 0
2 years ago
Read 2 more answers
L = loudness, in decibels (dB); I = sound intensity, in watts/m2; I0 = 10−12 watts/m2
irina [24]
The sound intensity of the Pile Driver is 39.5
 or nearly 40 times the sound intensity of the jackhammer.


Given with Loudness in dB for pile driver = 112 dB
We have to convert it in terms of sound intensity.
First,
112dB/10 = 11.2 

Then we'll use this as exponent of 10
(10)^(11.2) = 1.5849 * 10 ^ 11

Then use the equation of Watts per square meter to find the intensity:
I / (10^-12 W/m^2) =1.5849 * 10 ^ 11
I = sound intensity = 0.158

Then compare:

Sound intensity of Pile Driver/ Sound intensity of Jackhammer
(0.158) / (0.004)
= 39.5
or nearly 40 times the jackhammer.
3 0
2 years ago
Read 2 more answers
Malika charges $7.20 per hour for babysitting. She babysits 4 hours each week. She spends $10 per week and puts the rest of her
Juliette [100K]
$7.20        $28.8        $18.8        $225.6        $225.6
        4        $10              12                   .25       $56.4
X___       -_____         X____      X_____    +_____
$28.8       $18.8          225.6          $56.4        $282

You multiply $7.20 by the 4 hours she's working and you'll get $28.80. Then you would subtract the $10 from your answer and get $18.80. Then you'd multiply $18.80 by 12 for the mouths she's working and get $225.60. Next you multiply $225.60 by .25 from the grandparents and get $56.40. Finally you add $225.60 to $56.40 and get $282 in her savings account.
5 0
2 years ago
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