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mylen [45]
2 years ago
5

All side lengths of ΔJKL equal 2 units. A transformation maps ΔJKL to ΔJ'K'L'. The length of side J'K' is 5 units. Is this a rig

id transformation?
No, there is no one-to-one mapping of all the points of the pre-image to the image.
No, at least one segment length is not preserved, making this a nonrigid transformation.
Yes, the vertices of the pre-image map to the vertices of the image.
Yes, all of the side lengths of the pre-image are proportionate to the image.
Mathematics
2 answers:
S_A_V [24]2 years ago
5 0
No because at least one segment length is not preserved.
rigid means everything stays the same, but orientation sometimes changes.
Lorico [155]2 years ago
4 0
The answer is the second option
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A person is standing 50 ft from a statue. The person looks up at an angle of elevation of 8o when staring at the top of the stat
Lyrx [107]

Answer:

h=50.25\ ft

Step-by-step explanation:

<u>Right Triangles </u>

In a right triangle, one of the internal angles is 90°. When this happens, there is always a longer side, called hypotenuse and two shorter sides, called legs. They relate to Pythagoras's theorem. The basic trigonometric relations also stand, including

\displaystyle tan\alpha=\frac{a}{c}

where a is the opposite leg to \alpha and c is its adjacent led .

In our problem, we have a statue being looked by a person in such a way that the top of the statue forms an angle of 8° with the horizontal and the base of the statue forms an angle of 14° down. We also know the distance from the person to the statue is 50 ft. The situation is shown in the image below.

The height of the statue is h=a+b, where

a=50tan8^o

b=50tan14^o

Thus

h=50tan8^o+50tan14^o

h=50(tan8^o+tan14^o)

\boxed{h=50.25\ ft}

5 0
2 years ago
The statement below describes a situation in which opposite quantities combine to make 0. Is the statement true or false? A plan
Nadusha1986 [10]
I believe this is true....lets say the plane takes off and goes up 500 ft.....it circles, but then it has to come back down...land...so it comes down 500 ft...
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5 0
2 years ago
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The radius of the circular lens of a magnifying glass is 4 centimeters.
Nadusha1986 [10]

Answer: 50.24 square centimeters.

Step-by-step explanation:

Given: The radius of the circular lens of a magnifying glass = 4 centimeters

The area of a circle is given by :-

\text{Area}=\pi r^2, where r is the radius of the circle.

Then the area of the circular lens of a magnifying glass is given by :-

\text{Area}=\pi (4)^2=(3.14)(16)=50.24\text{ square centimeters }

Hence, the area of the circular lens of a magnifying glass = 50.24 square centimeters.

5 0
2 years ago
The quality control team of a company checked 800 digital cameras for defects. The team found that 20 cameras had lens defects,
dmitriy555 [2]

Answer:

0.025

Step-by-step explanation:

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P(lens)=\frac{Lens}{Total}\\\\=\frac{20}{800}\\\\=0.025

#Calculate the probability of a camera having a charging defect:

P(Charging)=\frac{Charging}{Total}\\\\=\frac{25}{800}\\\\=0.03125

The  the probability that a camera has a lens defect given that it has a charging defect is calculated as:

P(L|C)=\frac{P(C)P(L)}{P(C)}\\\\=\frac{0.025\times 0.03125}{0.03125}\\\\=0.025

Hence,  the probability that a camera has a lens defect given that it has a charging defect is 0.025

6 0
2 years ago
This dot plot is symmetric, and the data set has no extreme values. 2 4 5 6 7 8 9 10 What is the best measure of center for this
Zepler [3.9K]

I think it would be c

5 0
2 years ago
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