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frez [133]
2 years ago
3

A store gets a bucket of eggs for $16.20 and sells a dozen eggs for $3.50. If there are 450 eggs in the bucket, by what percent

has the store increased the price per dozen eggs?
Mathematics
1 answer:
Sav [38]2 years ago
8 0

Cost of bucket of eggs = $ 16.20

Number of eggs in the bucket= 450 eggs

Selling price  of Dozen of Eggs= $ 3.50

Cost price of 12 eggs

=\frac{16.20\times 12}{450}\\\\=0.432

The Percent by which the store increased the price per dozen eggs

  \frac{\text{Selling price}-\text{Cost price}}{Cost Price}\times 100\\\\ =\frac{3.50-0.432}{0.432}\times 100\\\\=\frac{3.068}{0.432}\times 100\\\\ 7.1018 \times 100=710.18

So, the percent by which the store increased the price per dozen eggs=710.18%(Approximately)

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2 years ago
At a certain airport, 75% of the flights arrive on time. A sample of 10 flights is studied. Assume each flight is independent of
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Answer:

52.56% probability that eight or more of the flights will arrive on time.

Step-by-step explanation:

For each flight, there are only two possible outcomes. Either it is on time, or it is not. The probability of a flight being on time is independent from other flights. So we use the binomial probability distribution to solve this question.]

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

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In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

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At a certain airport, 75% of the flights arrive on time.

This means that p = 0.75

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This means that n = 10

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P(X \geq 8) = P(X = 8) + P(X = 9) + P(X = 10)

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P(X = 8) = C_{10,8}.(0.75)^{8}.(0.25)^{2} = 0.2816

P(X = 9) = C_{10,9}.(0.75)^{9}.(0.25)^{1} = 0.1877

P(X = 10) = C_{10,10}.(0.75)^{10}.(0.25)^{0} = 0.0563

P(X \geq 8) = P(X = 8) + P(X = 9) + P(X = 10) = 0.2816 + 0.1877 + 0.0563 = 0.5256

52.56% probability that eight or more of the flights will arrive on time.

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2 years ago
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oksian1 [2.3K]

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