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iogann1982 [59]
2 years ago
6

if f(x)= 2x^2+5sqrt(x-2), complete the following statement: The domain for f(x) is all real numbers _____ than or equal to 2. (f

ill in the blank)

Mathematics
1 answer:
SCORPION-xisa [38]2 years ago
7 0

Answer:

Greater.

Step-by-step explanation:

The in the function  f(x)=2x^2+5\sqrt{x-2}, the square root term \sqrt{x-2} has to give a real number if f(x) is to be real. This can only happen if x\geq 2 because if x then \sqrt{x-2} will give a complex number and therefore f(x) will not be real.

Thus, the domain for f(x) is all real numbers<em><u> greater</u></em><u> </u>than or equal to 2.

You might be interested in
Test 24,515 for divisibility by 2, 3, 5, 9, or 10.
lord [1]

Answer:

D

Step-by-step explanation:

1. When a number is divisible by 2 it must end with even digit 0, 2, 4, 6 or 8.

So the number 24,515 is not divisible by 2.

2. When a number is divisible by 5 it must end with  digit 0,  or 5.

The number 24,515 ends with 5 so it is divisible by 5.

3. When a number is divisible by 3, the sum of all digits must be divisible by 3.

The sum of all digits of the number 24,515 is 2+4+5+1+5=17. 17 is not divisible by 3, so the number 24,515 is not divisible by 3.

4. When a number is divisible by 9, the sum of all digits must be divisible by 9.

The sum of all digits of the number 24,515 is 2+4+5+1+5=17. 17 is not divisible by 9, so the number 24,515 is not divisible by 9.

5. When a number is divisible by 10 it must end with  digit 0.

The number 24,515 ends with 5 so it is not divisible by 10.

8 0
2 years ago
Two cones are similar. The surface area of the larger cone is 65π square inches. The surface area of the smaller cone is 41.6π s
devlian [24]

Answer:

8 inches

Step-by-step explanation:

The surface area of a cone (without the base) is given by:

Surface area = pi*r*s

Where r is the base radius and s is the slant height.

The smaller cone has a surface area of 41.6pi in2 and a radius of 6.4 inches, so the slant height is:

41.6pi = pi*r*s

41.6 = 6.4s

s = 6.5 in

If the cones are similar, the radius and the slant height increase in the same proportion, so we have that:

r'/s' = r/s = 6.4/6.5

s' = r'*6.5/6.4

So for the larger cone, we have:

65pi = pi*r'*s'

65 = r'*r'*6.5/6.4

r'^2 = 64

r' = 8 inches

5 0
2 years ago
Read 2 more answers
Let P and Q be polynomials with positive coefficients. Consider the limit below. lim x→[infinity] P(x) Q(x) (a) Find the limit i
jenyasd209 [6]

Answer:

If the limit that you want to find is \lim_{x\to \infty}\dfrac{P(x)}{Q(x)} then you can use the following proof.

Step-by-step explanation:

Let P(x)=a_{n}x^{n}+a_{n-1}x^{n-1}+\cdots+a_{1}x+a_{0} and Q(x)=b_{m}x^{m}+b_{m-1}x^{n-1}+\cdots+b_{1}x+b_{0} be the given polinomials. Then

\dfrac{P(x)}{Q(x)}=\dfrac{x^{n}(a_{n}+a_{n-1}x^{-1}+a_{n-2}x^{-2}+\cdots +a_{2}x^{-(n-2)}+a_{1}x^{-(n-1)}+a_{0}x^{-n})}{x^{m}(b_{m}+b_{m-1}x^{-1}+b_{n-2}x^{-2}+\cdots+b_{2}x^{-(m-2)}+b_{1}x^{-(m-1)}+b_{0}x^{-m})}=x^{n-m}\dfrac{a_{n}+a_{n-1}x^{-1}+a_{n-2}x^{-2}+\cdots +a_{2}x^{-(n-2)}+a_{1}x^{-(n-1)})+a_{0}x^{-n}}{b_{m}+b_{m-1}x^{-1}+b_{n-2}x^{-2}+\cdots+b_{2}x^{-(m-2)}+b_{1}x^{-(m-1)}+b_{0}x^{-m}}

Observe that

\lim_{x\to \infty}\dfrac{a_{n}+a_{n-1}x^{-1}+a_{n-2}x^{-2}+\cdots +a_{2}x^{-(n-2)}+a_{1}x^{-(n-1)})+a_{0}x^{-n}}{b_{m}+b_{m-1}x^{-1}+b_{n-2}x^{-2}+\cdots+b_{2}x^{-(m-2)}+b_{1}x^{-(m-1)}+b_{0}x^{-m}}=\dfrac{a_{n}}{b_{m}}

and

\lim_{x\to \infty} x^{n-m}=\begin{cases}0& \text{if}\,\, nm\end{cases}

Then

\lim_{x\to \infty}=\lim_{x\to \infty}x^{n-m}\dfrac{a_{n}+a_{n-1}x^{-1}+a_{n-2}x^{-2}+\cdots +a_{2}x^{-(n-2)}+a_{1}x^{-(n-1)}+a_{0}x^{-n}}{b_{m}+b_{m-1}x^{-1}+b_{n-2}x^{-2}+\cdots+b_{2}x^{-(m-2)}+b_{1}x^{-(m-1)}+b_{0}x^{-m}}=\begin{cases}0 & \text{if}\,\, nm \end{cases}

3 0
2 years ago
A fox sees a rabbit 35 feet away and starts chasing it. As soon as the fox starts moving the rabbit sees it and starts running a
Artemon [7]

The speed of the fox should be greater than the rabbit's speed in other to catch up, Hence, the speed of the fox must be 35/t + 40

The distance between the rabbit and fox, d = 35 feets

The rabbit's speed = 40 feets per second

Fox's speed = F

In other to obtain a specific speed for the fox, the time at which the fox is required to catch up with the rabbit should be given.

Let the time = t

Recall :

Speed = distance / time

Distance = speed × time

Rabbit's distance from fox after time t will be :

35 + (40 × t) = 35+40t

Fox's distance after time, t = fox speed × t = F × t

In other to catch up ; both fox and rabbit must be at the same distance ;

Rabbit's distance at time t = Fox's distance at time t

35+40t = Ft

To solve for F which is the fox's speed:

Divide both sides by t

(35+40t) / t = Ft/t

35/t + 40 = F

Hence, the fox' s speed must be : 35/t + 40

To obtain the exact speed of the fox, we must be given a specific time value.

Learn more : brainly.com/question/18112348

4 0
2 years ago
Clayton surveyed a random sample of 90 registered voters in his hometown. He asked them if they were in favor of building a new
shepuryov [24]

10850 would be I'm favor of building the park and 4650 would not

6 0
2 years ago
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