All categories

2 years ago

What value of x will make the triangles similar by the SSS similarity theorem?

Mathematics

2 answers:

Damm [24]2 years ago

8 0

SSS similarity theorem states: If the corresponding sides of two triangles are proportional, then the two triangles are similar.

You have two isosceles triangle, then if

$\dfrac{44}{20}=\dfrac{x}{35},\\ \\x=\dfrac{44\cdot 35}{20}=11\cdot 7=77,$

two isosceles triangles will be similar by SSS theorem.

Answer: correct choice is C.

Bingel [31]2 years ago

6 0

Answer: It’s C I just took the test!!

Step-by-step explanation:

Good Luck!

You might be interested in

I need the answers thanks :)

bogdanovich [222]

1.) y=3
2.) y=13
2y + y = 3y , 22+17= 39
3y = 39 , divide 3 on each side (which cancels out the 3 with the y which leaves you with y)
3.) y=10
3y - y = 2y , 35-15= 20
2y=20 , do the same as # 2.
4.) y=4
9y - 5y = 4y , 48-32= 16
4y=16, do the same as #2 & #3
5.) (4,5)
x + 3y = 19
2x - 3y = -7
solve for x first ; x + 2x= 3x , 19-7 = 12; 3x = 12 ; divide 3 ; x= 4. You know have to make the x's cancel out. so I will multiply -2 on the first equation. -2(x+3y=19)
-2x - 6y = -38
2x - 3y = -7
Now solve for y ; -6y + -3y = -9y , -38 + -7 = -45; -9y=-45 ; divide by -9 (since they are both negative your answer will be positive) ; y= 5
6.) (6,8)
x + 4y = 38
-x - 3y = -30
solve for y first ; 4y - 3y = y , 38-30 = 8; y=8 (that simple!) Now you need to find a common multiple for 4 & 3 which is 12. So you will have to multiply each equation by either 4 or 3.
(x + 4y = 38)*3 = 3x + 12y = 114
(-x - 3y = -30)*4 = -4x - 12y = -120
solve for x ; 3x - 4x = -x , 114-120= -6 ; -x=-6. Since the x has a negative that means there's still a 1 there so -1x=-6 ; you will need to divide this which makes the 6 a positive; x=6

8 0

2 years ago

Sarah’s stands on a ground and sights the top of a steep Clift at a 60 degree angle of elevation she then steps back 50 meters t

SashulF [63]

Answer:

Cliff is 45 m tall.

Step-by-step explanation:

Given:

Height of Sarah = 1.8 m

Angle of elevation = 60°

Angle of elevation 50 m back = 30°

As shown in the figure we have two right angled triangles SPQ and SPR.

Let the height of the cliff be $h$ meters and $h= h_1+h_s$ .

Using trigonometric ratios:

tan (Ф) = opposite/adjacent

In ΔSPQ. In ΔSPR.

⇒ $tan(60) = \frac{h_1}{x}$ ...equation (i) ⇒ $tan (30)=\frac{h_1}{x+50}$ ...equation (ii)

Dividing equation (i) and (ii)

⇒ $\frac{tan(60)}{tan(30)} = \frac{h_1}{x} \times \frac{x+50}{h_1}$

⇒ $3 = \frac{x+50}{x}$

⇒ $3x=x+50$

⇒ $3x-x=50$

⇒ $2x=50$

⇒ $x=\frac{50}{2}$

⇒ $x=25$ meters

To find $h_1$ plugging $x=25$ in equation (i)

⇒ $h_1=x\times tan(60)$

⇒ $h_1=25\times 1.73$

⇒ $h_1=43.25$ meters

The height of the cliff from ground :

⇒ $h= h_1+h_s$

⇒ $h= 43.25+1.8$

⇒ $h=45.05$ meters

The cliff is 45 m tall to the nearest meter.

8 0

2 years ago

A company manufactures women's hosiery. the company sells slightly irregular panty hose through a mail-order catalog service. if

erik [133]

A Company manufactures women's hosiery. The company sells slightly irregular panty hose through a mail-order catalog service. If the company produces 300,000 pairs of hose per day and the probability of a pair not being irregular is 0.92, the average number that will be available for the catalog order department is:
a.22080
b.148.59
c.24000
d.154.92
e.15.49

ANS:<span>C</span>

8 0

2 years ago

Suppose the area that can be painted using a single can of spray paint is slightly variable and follows a nearly normal distribu

Svetllana [295]

Answer:

Step-by-step explanation:

Hello!

You have the variable

X: Area that can be painted with a can of spray paint (feet²)

The variable has a normal distribution with mean μ= 25 feet² and standard deviation δ= 3 feet²

since the variable has a normal distribution, you have to convert it to standard normal distribution to be able to use the tabulated accumulated probabilities.

P(X>27)

First step is to standardize the value of X using Z= (X-μ)/ δ ~N(0;1)

P(Z>(27-25)/3)

P(Z>0.67)

Now that you have the corresponding Z value you can look for it in the table, but since tha table has probabilities of $P(Z$ , you have to do the following conervertion:

P(Z>0.67)= 1 - P(Z≤0.67)= 1 - 0.74857= 0.25143

There was a sample of 20 cans taken and you need to calculate the probability of painting on average an area of 540 feet².

The sample mean has the same distribution as the variable it is ariginated from, but it's variability is affected by the sample size, so it has a normal distribution with parameners:

X[bar]~N(μ;δ²/n)

So the Z you have to use to standardize the value of the sample mean is Z=(X[bar]-μ)/(δ/√n)~N(0;1)

To paint 540 feet² using 20 cans you have to paint around 540/20= 27 feet² per can.

P(X≤27) = P(Z≤(27-25)/(3/√20))= P(Z≤2.98)= 0.999

No. If the distribution is skewed and not normal, you cannot use the normal distribution to calculate the probabilities. You could use the central limit theorem to approximate the sampling distribution to normal if the sample size was 30 or grater but this is not the case.

I hope it helps!

4 0

2 years ago

Your poor health causes you to miss one work day every two weeks. You do not get paid when you are out sick. You normally work 8

klio [65]

52 weeks in a year. half that is 26 weeks. you miss 26 days a year 8 x 9.20= 73.60 x 26 = $1913.60 per year lost

4 0

2 years ago