Answer:
All in all, Jonathan's piggy bank contains 100 coins. Among these coins, only 50 are one-dollar coins. Therefore, the theoretical probability of picking one-dollar coin from the piggy bank is equal to 50/100 or 1/2.
Similarly, from the experiment, 20 coins were picked and among these there are 12 one-dollar coins. The answer to the second question is therefore 12/20 or 3/5.
Step-by-step explanation:
Jake spent a total of 70 cents.
b = black-and-white = 8 cents
c = color = 15 cents
70 = 8b + 15c
he made a total of 7 copies
b + c = 7
system of equation:
70 = 8b + 15c
b + c = 7
--------------------------
b + c = 7
b + c (-c) = 7 (-c)
b = 7 - c
plug in 7 - c for b
70 = 8(7 - c) + 15c
Distribute the 8 to both 7 and - c (distributive property)
70 = 56 - 8c + 15c
Simplify like terms
70 = 56 - 8c + 15c
70 = 56 + 7c
Isolate the c, do the opposite of PEMDAS: Subtract 56 from both sides
70 (-56) = 56 (-56) + 7c
14 = 7c
divide 7 from both sides to isolate the c
14 = 7c
14/7 = 7c/7
c = 14/7
c = 2
c = 2
---------------
Now that you know what c equals (c = 2), plug in 2 for c in one of the equations.
b + c = 7
c = 2
<em>b + (2) = 7
</em><em />Find b by isolating it. subtract 2 from both sides
b + 2 = 7
b + 2 (-2) = 7 (-2)
b = 7 - 2
b = 5
Jake made 5 black-and-white copies, and 2 color copies
hope this helps
1. 100 * 20
2. 7 hours
3. 141 kilometers
4. 8.5 hours
5. 55.75 mi/h
2.47*10^8=247000000
take 2.47 and move the decimal point 8 times to the right. Fill empty spaces with zeros
Answer:
Below is the procedure that was used to find the answer.
Step-by-step explanation:
Let be "e" the weight in pounds of the elephant and "c" the weight in pounds of the cat.
According to the information provided in the exercise, we know that The weight of an elephant is 
times the weight of a cat. Based on this we can write the following equation:
If the weight in pounds of the elephant is:
We must substitute this value into the equation and then solve for "c" in order to find the weight in pounds of the cat.
Then we get:
