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Soloha48 [4]
2 years ago
14

A company manufactures women's hosiery. the company sells slightly irregular panty hose through a mail-order catalog service. if

the company produces 300,000 pairs of hose per day and the probability of a pair not being irregular is 0.92, the average number that will be available for the catalog order department is:
Mathematics
1 answer:
erik [133]2 years ago
8 0
A Company manufactures women's hosiery. The company sells slightly irregular panty hose through a mail-order catalog service. If the company produces 300,000 pairs of hose per day and the probability of a pair not being irregular is 0.92, the average number that will be available for the catalog order department is:
a.22080
b.148.59
c.24000
d.154.92
e.15.49

ANS:<span>C</span>
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Let , coordinate of points are P( h,k ).

Also , k = 3h + 1

Distance of P from origin :

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Two window washers start at the heights shown. (A: 21 ft high rising 8 in per second. The other is 50 feet high descending 11inc
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For this case, the first thing we are going to do is write the generic equation of motion for the vertical axis.

We have then:

h = \frac {1} {2} gt ^ 2 + vo * t + h0

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  • <em>vo: initial speed </em>
  • <em>h0: initial height </em>

For the first body:

h1 = \frac {1} {2} gt ^ 2 + \frac {8} {12} * t + 21

For the second body:

h2 = \frac {1} {2} gt ^ 2 - \frac {11} {12} * t + 50

By the time both bodies have the same height we have:

h1 = h2\\

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\frac {8} {12} * t + 21 = - \frac {11} {12} * t + 50

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2 years ago
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On the first day a total of 40 items were sold for $356. Define the variables and write a system of equations to find the number
Alina [70]
<h3><u><em>Question:</em></u></h3>

On the first day, a total of 40 items were sold for $356. Pies cost $10 and cakes cost $8. Define the variables, write a system of equations to find the number of cakes and pies sold, and state how many pies were sold.

<h3><em><u>Answer:</u></em></h3>

The variables are defined as:

"c" represent the number of cakes sold and "p" represent the number of pies sold

The system of equations used are:

c + p = 40 and 8c + 10p = 356

18 pies and 22 cakes were sold

<h3><em><u>Solution:</u></em></h3>

Let "c" represent the number of cakes sold

Let "p" represent the number of pies sold

Cost of 1 pie = $ 10

Cost of 1 cake = $ 8

Given that total of 40 items were sold

number of cakes + number of pies = 40

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<u><em>Given items were sold for $356</em></u>

number of cakes sold x Cost of 1 cake + number of pies sold x Cost of 1 cake = 356

c \times 8 + p \times 10 = 356

8c + 10p = 356  ----- eqn 2

<u><em>Let us solve eqn 1 and eqn 2</em></u>

From eqn 1,

p = 40 - c    ---- eqn 3

Substitute eqn 3 in eqn 2

8c + 10(40 - c) = 356

8c + 400 - 10c = 356

-2c = - 44

c = 22

<em>Substitute c = 22 in eqn 3</em>

p = 40 - c

p = 40 - 22

p = 18

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1 year ago
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