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Triss [41]
2 years ago
10

Calculate the resistance of a piece of aluminum wire with a diameter of 100 mils and a length of two miles, at 68°F. Hint: Be su

re to first convert mils to cmils and use the K value for aluminum found in the reference. (Round the FINAL answer to two decimal places.)
Mathematics
1 answer:
Oduvanchick [21]2 years ago
4 0
First you need to know the formula of the Resistance(R) of a conductor, which is:

R =  \frac{K*L}{CM} -- (A)

Where,
R = Resistance of the wire = ?
K = Specific resistance of the wire(In this case Aluminum at 68°F) = 17.02 ohm-circular-mil-foot
L = Length of the wire(in feet)
CM = Circular mil Area(In inches)


Now in order to use the above formula(A), we have to first convert TWO quantities:
1) The length of the wire(from miles to feet)
2) Mils to Circular mil Area

1.
The length of the wire given = 2 miles
The length of the wire(In feet) = 10560 ft
2.
Since the mils given = 100 mils.
Therefore,
Circular mils(Circular mil Area) = mils x mils = 100 x 100 = 10000 

Now plug-in the values in equation(A):

A=> R = \frac{17.02 * 10560}{10000 }

R = 17.97 ohms 

Ans: Resistance of the aluminum wire = 17.97 ohms.

-i
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11) The Cost of maintaing a
dezoksy [38]

Answer:

a). Cost of 44 pupils = $14265

b). Least number of pupils = 31

Step-by-step explanation:

The given question is incomplete; here is the complete question.

The cost of maintaining a school is partly constant and partly varies as the number of pupils. With 50 pupils, the cost is $15,705.00 and with 40 pupils, it is $13,305.00.

(a) Find the cost when there are 44 pupils.

(b) If the fee per pupil is $360.00, what is the least number of pupils for which the school can run without a loss?

Let the equation representing the total cost of maintaining a school is,

C = ax + b

Where C = Total cost of maintaining a school

a = Fee per pupil

b = Fixed running cost

x = number of pupils

a). Cost of 50 pupils = $15705

    Equation will be,

    15705 = 50a + b -------(1)

    Cost of 40 pupils = $13305

    Equation will be,

    13305 = 40a + b --------(2)

    By subtracting equation (2) from equation (1),

    15705 - 13305 = (50a + b) - (40a + b)

    2400 = 10a

    a = 240

    From equation (1),

    b = 3705

    Equation representing the total cost will be,

    C = 240x + 3705

    If x = 44

    C = 240(44) + 3705

    C = $14265

b). If the fee per pupil 'a' = $360

    Let the number of pupils = p

    Total fee of 'p' pupils = $360p

    Total cost to run the school will be = 3705 + 240p

    For the school not to be in the loss,

    360p ≥ 3705 + 240p

    360p - 240p ≥ 3705

    120p ≥ 3705

    p ≥ \frac{3705}{120}

    p ≥ 30.875

    Therefore, to run the school without loss, number pupils should be at least 31.

3 0
2 years ago
Nate is creating a PSA about building a "green” roof. Which source is most reliable for his research? a blog post written by a c
galina1969 [7]

Answer:

Nate wants to use a .org (or .gov) site about ecological roofs, a book featuring photos of different styles of room  because

1. It specifically talks about green roof's

2. Unlike the blog post, the .org/.gov is not attempting to sell a product that may change how the article is written.

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2 years ago
The electric potential in a circuit is given by
11111nata11111 [884]
400 v .300.500.87067
7 0
2 years ago
The two lines, P and Q, are graphed below: Line P is drawn by joining ordered pairs negative 8,15 and 6, negative 12. Line Q is
andreyandreev [35.5K]

Solution:

Keep in mind ,

Equation of line joining two points (a,b) and (p,q) is given by :

     \frac{q-b}{p-a}=\frac{y-b}{x-a}

Equation of line P which is obtained by  joining  (- 8,15) and (6, - 12) is given by:  

\frac{y-15}{x+8}=\frac{-12-15}{6+8}\\\\ 14(y-15)=-27(x+8)\\\\ 14 y -210= -27 x - 216\\\\ 27 x+14 y+6=0

Equation of line Q which is obtained by  joining  (4,16) and (-9, 10) is given by:  

\frac{y-16}{x-4}=\frac{16-10}{4+9}\\\\ 13(y-16)=6(x-4)\\\\ 13 y -208= 6 x - 24\\\\ 6 x-13 y+184=0

Equation of line P and Q are

27 x+14 y+6=0-------(1)× 2

6 x-13 y+184=0-------(2)× 9

54 x + 2 8 y+12=0---(1)

54 x -117 y +1656=0----(2)

(1) - (2)

145 y= 1644

y=11.33,

27 x+14 y+6=0-------(1)×13

6 x-13 y+184=0-------(1)×14

351 x + 182 y + 78=0-----(1)

84 x - 182 y +2576=0----(2)

(1) + (2)

435 x + 2654=0

x = - 6.11

So, solution set is (-6.11, 11.33)

Option (C) is true. (−2, 4), because this point makes both the equations incorrect.


8 0
2 years ago
A ketchup company regularly receives large shipments of tomatoes. For each shipment that is received, a supervisor takes a rando
fredd [130]

Answer:

H_o:p=0.1\\\\H_a:p\neq 0.1

Step-by-step explanation:

-A hypothesis is a claim of evidence and is used in making statistical decisions during experiments/ research.

-Given that 10% of the entire shipment is bruised.

-the null hypothesis states that the proportion is equal to the stated value:

H_o:p=0.1

-The alternative  states that the null hypothesis is not correct:

H_a:p\neq 0.1

8 0
2 years ago
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