Answer:

Step-by-step explanation:
Given that from a well shuffled set of playing cards (52 in number) a card is drawn and without replacing it, next card is drawn.
A - the first card is 4
B - second card is ace
We have to find probability for

P(A) = no of 4s in the deck/total cards = 
After this first drawn if 4 is drawn, we have remaining 51 cards with 4 aces in it
P(B) = no of Aces in 51 cards/51 = 
Hence

(Here we see that A and B are independent once we adjust the number of cards. Also for both we multiply the probabilities)
P = It is a weekend
Q = I will exercise
If "It is a weekend", then "I will exercise"
But "It is NOT a weekend"
Therefore, "I will NOT exercise"
Using P and Q our statement would look like this,
If P, then Q
But not P
Therefore not Q
Or symbolically like this:
P -> Q
~P

~Q
I'm sorry that this doesn't match up with the options you posted.
Maybe they didn't paste correctly.
Answer:
<u><em>(x, y) -------> ( - x , y - 10 )</em></u>
Step-by-step explanation:
Titus is not correct.
There are two transformations will correctly prove FEDCBA ≅ F'E'D'C'B'A'
First transformation is Reflection over y-axis , then translation 10 units down.
The final formula is <em>( - x , y - 10 )</em>