Answer:
The repair/reboot time needs to be reduced by 600 hours so as to increase availability time by 5%.
Step-by-step explanation:
To increase availability by 5%, the amount of hours of availability is multiplied 105%.
therefore 1.05 × 12000 = 12600 hours
Therefore the repair/reboot time needs to be reduced by 600 hours.
Answer: in order to qualify, the time must be at least 15.93 minutes
Step-by-step explanation:
Let x be a random variable representing the average response times of fire departments to fire calls. Since it follows a normal distribution, we will determine the z score by applying the formula,
z = (x - µ)/σ
Where
x = sample mean
µ = population mean
σ = population standard deviation
From the information given,
µ = 12.8 minutes
σ = 3.7 minutes
in order to qualify for the special safety award, the probability value would be to the right of the z score corresponding to 80%
The z score corresponding to 80% on the normal distribution table is 0.845
Therefore,
0.845 = (x - 12.8)/3.7
0.845 × 3.7 = x - 12.8
3.13 = x - 12.8
x = 12.8 + 3.13 = 15.93
80km: 1h=60 minutes
?km: 45 minutes
The distance between two jungles is: 45 x 80 : 60 =60 km
<span>D) Angles BAC and DCA are congruent by the Alternate Interior Angles Theorem.</span>
For this case what we can do is the following rule of three:
54.99 ------> 100%
32.99 ------> x
We clear the value of
x = (32.99 / 54.99) * (100)
x = 59.99272595
Therefore, the discount percentage is:
100-59.99272595 = 40.00727405%
To the nearest percent;
40%
Answer:
The percent markdown of the coat is:
40%
