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2 years ago

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A set of cards contains the numbers 1 through 20. Mathieu chooses a card a random, records the number of the card, and then retu

rns the card to the set. He conducts 200 trials of this event. Based on the theoretical probability, how many times can Mathieu expect to choose a multiple of 5?

2 answers:

Korvikt [17]2 years ago

8 0

Chance of multiple of 5 is 4 / 20 or 1 / 5.
This means that the answer is 200 / 5
Answer = 40

Sidana [21]2 years ago

3 0

Answer: There are 40 times that Mathieu can expect to choose a multiple of 5.

Step-by-step explanation:

Since we have given that

Numbers between 1 to 20 = 20

Numbers which are divisible by 5 = 4

i.e. {5,10,15,20}

So, Probability that getting a number divisible by 5 is given by

$\dfrac{4}{20}=\dfrac{1}{5}$

If the number of trials = 200

Then, Number of times Mathieu expect to choose a multiple of 5 is given by

$\dfrac{1}{5}\times 200\\\\=40$

Hence, there are 40 times that Mathieu can expect to choose a multiple of 5.

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A customer borrowed $2000 and then a further $1000 both repayable in 12 months. What should he have saved if he had taken out on

Neporo4naja [7]

Answer:

a. $60

Step-by-step explanation:

We will use simple interest formula to solve our given problem.

$A=P(1+rt)$ , where

A= Amount after t years.

P= Principal amount.

r= Interest rate in decimal form.

t= Time in years.

Let us find amount of loans repayable after 12 months for taking two amounts of $2000 and $1000.

As $2000 and $1000 are less than 2500, so the rate of loan will be 10%.

$10\%=\frac{10}{100}=0.10$

12 months = 1 year.

$A=2000(1+0.10\times 1)$

$A=2000(1+0.10)$

$A=2000(1.10)$

$A=2200$

Now let us find amount repayable after 12 months for borrowing $1000.

$A=1000(1+0.10\times 1)$

$A=1000(1+0.10)$

$A=1000(1.10)$

$A=1100$

Adding these amounts we will get total repayable amount after 12 months for borrowing $2000 and $1000 separately.

$\text{Amount repayable for borrowing two separate amounts}=2200+1100=3300$

Now let us find repayable amount after 12 months for taking 1 loan. As $3000 is between $2501 and $7500, so rate of loan will be 8%.

$8\%=\frac{8}{100}=0.08$

$A=3000(1+0.08\times 1)$

$A=3000(1+0.08)$

$A=3000(1.08)$

$A=3240$

Now let us find difference between both repayable loan amounts.

$\text{Difference between both repayable loan amounts}=3300-3240$

$\text{Difference between both repayable loan amounts}=60$

Therefore, the customer should have saved $60, if he had taken out one loan for $3000 and option a is the correct choice.

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Answer:

<u>The annual profit if the baker sells 400 pies would be US$ 12,800</u>

Step-by-step explanation:

1. Let's review the information provided to us to answer the question correctly:

Annual profit in dollars from selling pies using p n( ) = 52n − 0.05n² , where n is the number of pies sold

Annual sales of the baker = 400 pies

2. Let's solve p for 400 pies

p n( ) = 52n − 0.05n²

p (n₄₀₀) = 52 * 400 − 0.05 * 400²

p (n₄₀₀) = 20,800 − 0.05 * 160,000

p (n₄₀₀) = 20,800 − 8,000

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2 years ago

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Answer:

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Step-by-step explanation:

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and

$\begin{array}{cc}x&g(x)\\-3&\\-2&\\-1&\\0&\\1&\\2&\\3&\end{array}$

First, fill in the second table:

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Hence, the second table is

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The input value that produces the same output value in both charts is 2.

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Step-by-step explanation:

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Answer:

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