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2 years ago

Which early browser was the first to run on multiple computer platforms including windows?â?

Computers and Technology

1 answer:

zaharov [31]2 years ago

7 0

The answer is Mosaic

Also known as the NCSA Mosaic, the Mosaic was popularized as the WWW and the internet. It was a client for protocols like FTP, Gopher, and Network News Transfer Protocol.

Its reliability and simple installation all contributed to its popularity on the web and Microsoft operating Systems as well. At the time of its release in 1993, the Mosaic was free software available only on Unix. The NCSA, however, put Mosaic on both Mac and windows in the late 1993.

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_______________ is used by a hacker to mask intrusion and obtain administrator permissions to a computer.

Sergeu [11.5K]

Answer:

Rootkit.

Explanation:

Rootkit is a collection of software tools,mostly malicious.These are mostly used by hackers to obtain administrator permission to a computer by masking intrusion.

Root-kit is made from two word Root and kit.Where root refers to the name of privileged account on an operating system that is somewhat like unix and KIT refers to the tools used.

6 0

2 years ago

9. Which of the following are true for all regular languages and all homomorphisms? (a) h (L1 ∪ L2)= h (L1) ∩ h (L2). (b) h (L1

mixer [17]

Answer:

h (L1 ∪ L2)= h (L1) ∩ h (L2).

This is true.

There will be w ∈ (L1 ∪ L2) for any s ∈ h (L1 ∪ L2) in such a way that s=h(w)

we can assume that w ∈ L1

So In this case h(w) ∈ L (S1). Hence s ∈ L(S1)

for any s ∈ h (L1) U h(L2)

We can assume that s ∈ L(S1)

There exists w ∈ L1 such that s= h(w)

In this case it is w ∈ L1 U L2 as well.

Hence , s ∈ h (L1 U L2)

Explanation

consider = 0,1 and = a,b and h(0) = a , h(1) = ab

(a) Consider L1 = 10,01 and L2 = 00,11

Now L1 ∪ L2 = 00,01,10,11

h (L1 ∪ L2) = h(00) , h(01) , h(10) , h(11) = h(0)h(0) , h(0)h(1) , h(1)h(0) , h(1)h(1)

= aa, aab , aba , abab

Hence h (L1 ∪ L2) = aa, aab , aba , abab .

Here h (L1) = h(10) , h(01) = h(1)h(0) , h(0)h(1) = aba , aab

Hence h (L1) = aba , aab .

Here h (L2) = h(00) , h(11) = h(0)h(0), h(1)h(1) = aa, abab

Hence h(L2) = aa, abab.

Finally Hence , h (L1 ∪ L2)= h (L1) ∩ h (L2).

5 0

2 years ago

A half-life is the amount of time it takes for a substance or entity to fall to half its original value. Caffeine has a half-lif

Ivan

Answer:

// program in C++.

#include <bits/stdc++.h>

using namespace std;

// main function

int main() {

// variable

float n;

cout<<"Enter the initial value:";

//Read the input from the user

cin>>n;

//Declare variables for storing values at 6, 12 and 18 hours

float hours_6, hours_12, hours_18;

//Set precision level of floating point number

cout << fixed;

cout << setprecision(6);

//calculate values at 6, 12 and 18 hours

hours_6 = n / 2.0;

hours_12 = hours_6 / 2.0;

hours_18 = hours_12 / 2.0;

//display the output

cout<<"After 6 hours: "<<hours_6<<"mg"<<endl;

cout<<"After 12 hours: "<<hours_12<<"mg"<<endl;

cout<<"After 18 hours: "<<hours_18<<" mg"<<endl;

return 0;

}

Explanation:

Read an input from the user. Set the precision to 6 for displaying the result up to 6 decimal places. The first half life at 6 hours can be calculated by dividing the input by 2. The half life at 12 hours can be found out by dividing the half life value at 6 hours by 2. Similarly at 18 hours, we find the half life value by dividing the half life value at 12 hours by 2.

Output:

Enter the initial value:100

After 6 hours: 50.000000 mg

After 12 hours: 25.000000 mg

After 18 hours: 12.500000 mg

5 0

2 years ago

Strlen("seven"); what is the output?

Leokris [45]

Answer:

A is your answer hope this helps

4 0

2 years ago

Jane is designing a print brochure for a retail company. She’s having trouble deciding on the page margin. Which best practice w

8090 [49]

I think the answer will be C

7 0

2 years ago

Read 2 more answers