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disa [49]
2 years ago
15

Keshia is riding her bike on bay view bike path. Keyshia’s bike got on a flat tire 2/3 of the way down the path and she had to s

top.How far did keyshia ride?
Mathematics
2 answers:
almond37 [142]2 years ago
8 0
She rode her bike 27%
Anastaziya [24]2 years ago
3 0
You just said the answer. She rode 2/3 of the way, or 66.6 % repeating which rounds to 67%.
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Let m,n,p, and q represent nonzero positive integers. find a number in terms of m,n,p, and q that is halfway between m/n and p/q
alukav5142 [94]
This is the same as averaging. You add them and divide by 2.

((m/n) + (p/q))/2 would be a number in between m/n and p/q.

Do note that n and q must be nonzero, but luckily that is a given.
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2 years ago
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Which are steps in the process of completing the square used to solve the equation 3 – 4x = 5x2 – 14x? Check all that apply. 3 =
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B)3 = 5x2<span> – 10</span><span>x
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Select all of the answers below that are equivalent to T = {Tinkey-Winky, Laa-Laa,
stepan [7]

Answer:

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  • {clothes, glass, car, greeting card}

Step-by-step explanation:

The options that will be equivalent to T will have to be the options that have the same Cardinality as T. Cardinality refers to the number of elements in a set and in the set T, there are 4 elements being Tinkey-Winky, Laa-Laa,  Dipsy, Po so the Cardinality is 4.

The equivalent sets would therefore be sets with a cardinality of 4 as well and those are;

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2 years ago
Solving for a Confidence Interval: Algebra 2 points possible (graded) In the problems on this page, we will continue building th
baherus [9]

Answer:

Step-by-step explanation:

1) The given inequality is

|\sqrt{n} \frac{(\bar R_n-p)}{\sqrt{p(1-p)} } |

\to n( \bar R _n - p)^2

\to n\bar R +np^2-2nR_np

Arranging the terms  with p² and p, we get

p^2(n+q^2_{\alpha /2)-p(2n \bar R _n+q^2_{\alpha / 2})+n \bar R ^2 _n

Hence, the inequality is of the form

Ap² + Bp + c < 0

2. A quadratic equation of the form

Ap² + Bp + c < 0 with A > 0 looks like

<u>Check the attached image</u>

The region where the values are negative lies between p₁ and p₂ ...

The p₁ < p < p₂

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2 years ago
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