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STatiana [176]
2 years ago
10

Ten students compared the amount (in dollars) they spent on books each week. The box plot shows the results. The median amount t

hey spent each week is ____ ($20,$30,$40,$50) . The difference of the first and third quartiles of the data set is ____ ($15,$30,$45,$60).

Mathematics
2 answers:
belka [17]2 years ago
7 0
The median is 50.
The first quartile is 20, the third is 65, the difference is 45.
RUDIKE [14]2 years ago
7 0

The box plot contains a box and 5 points:

  1. 1st point is the left endpoint (the smallest number);
  2. 5th point is the right endpoint (the greatest number);
  3. 2nd point is Q_1 - first quartile;
  4. 3rd point is Q_2 - second quartile = median;
  5. 4th point is Q_3 - third quartile.

Then the median is $50,  and Q_3-Q_1=\$65-\$20=\$45.

Answer: $50; $45.

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The National Center for Education Statistics would like to test the hypothesis that the proportion of Bachelor's degrees that we
agasfer [191]

This question involves the hypothesis test for the proportion. First we build the hypothesis, then find the test statistic, and according to the test statistic, we get the following answer:

The conclusion for this hypothesis test would be that because the absolute value of the test statistic is less than the critical value of 1.645, we do not reject the null hypothesis that the proportion of Bachelor's degrees that were earned by women equals 0.60.

The National Center for Education Statistics would like to test the hypothesis that the proportion of Bachelor's degrees that were earned by women equals 0.60

This means that at the null hypothesis, it is tested if the proportion is of 0.6, that is:

H_0: p = 0.6

At the alternative hypothesis, we test if the proportion is different of 0.6, that is:

H_1: p \neq 0.6

Decision rule:

Two-tailed test(test if the proportion is different of a value), so we exclude the top and bottom 0.1/2 = 0.05, meaning that looking at the z-table, we find a critical value of |Z_c| = 1.645, and the decision rule is:

Accept the null hypothesis: |Z| < 1.645

Reject the null hypothesis: |Z| > 1.645

Test statistic:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

In which X is the sample mean, \mu is the value tested at the null hypothesis, \sigma is the standard deviation and n is the size of the sample.

0.6 is tested at the null hypothesis:

This means that \mu = 0.6, \sigma = 0.4

75 out of a sample of 140:

This means that:

n = 140, \pi = \frac{75}{140} = 0.5357

Value of the test statistic:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

z = \frac{0.5357 - 0.6}{\frac{\sqrt{0.6*0.4}}{\sqrt{140}}}

z = -1.55

So |z| = 1.55

Decision:

The conclusion for this hypothesis test would be that because the absolute value of the test statistic is less than the critical value of 1.645, we do not reject the null hypothesis that the proportion of Bachelor's degrees that were earned by women equals 0.60.

For a similar example, you can check brainly.com/question/24166849

7 0
2 years ago
Ardi and lei are both travelling by train. Ardi’s train travels 70km in 35 minutes. Lei’s train travels 585km. It leaves at 9:05
LuckyWell [14K]

Answer:47.14km/h

Step-by-step explanation:

585÷3 and 1/2=167.14km/h

70÷35/60=120km/h

167.14-120=47.14km/h

8 0
2 years ago
A clothing vendor estimates that 78 out of every 100 of its online customers do not live within 50 miles of one of its physical
Korolek [52]

Answer:

78% probability that a randomly selected online customer does not live within 50 miles of a physical​ store.

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

In this problem, we have that:

Total outcomes:

100 customers

Desired outcomes:

A clothing vendor estimates that 78 out of every 100 of its online customers do not live within 50 miles of one of its physical stores. So the number of desired outcomes is 78 customers.

Using this​ estimate, what is the probability that a randomly selected online customer does not live within 50 miles of a physical​ store?

p = \frac{78}{100} = 0.78

78% probability that a randomly selected online customer does not live within 50 miles of a physical​ store.

4 0
2 years ago
Marin writes the functions m(x) = StartFraction 3 x Over x + 7 EndFraction and n(x) = StartFraction 7 x Over 3 minus x EndFracti
Svetlanka [38]

Answer:

B.

Step-by-step explanation:

3 0
2 years ago
Read 2 more answers
y = A system of equations. y equals StartFraction one-half EndFraction x minus 6. x equals negative 4.x – 6 x = –4 What is the s
tatiyna

Answer: (-4,-8)

Step-by-step explanation: I got a 100% on the quiz

8 0
2 years ago
Read 2 more answers
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