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inna [77]
2 years ago
5

The data set represents the number of rings each person in a room is wearing. 0, 2, 4, 0, 2, 3, 2, 8, 6 What is the interquartil

e range of the data?
2
3
4
6
Mathematics
2 answers:
taurus [48]2 years ago
4 0
D1,..,d9 = 0,0,2,2,2,3,4,6,8  //there are 9 values, in ascending order
Q2 (median) = d5 = 2  //value in the middle
Q1 = (d2+d3) / 2 = (0+2)/2 = 1
(Q1 is middle value of d1,d2,d3,d4, but there is no middle element among four elements, that is why arithmetic mean is taken)
Q3 = (d7+d8) / 2 = (4+6)/2 = 5
interquantlie range = IQR = Q3 - Q1 = 5 -1 = 4
answer: 4

pogonyaev2 years ago
4 0

Answer:

Option C.

Step-by-step explanation:

The given data set is

0, 2, 4, 0, 2, 3, 2, 8, 6

Arrange the data in ascending order.

0, 0, 2, 2, 2, 3, 4, 6, 8

Divide the data set in 4 equal parts.

(0, 0), (2, 2), 2,( 3, 4), (6, 8)

Now, we get

Q_1=\dfrac{0+2}{2}=1

Q_2=Median=2

Q_3=\dfrac{4+6}{2}=5

The interquartile range formula:

IQR=Q_3-Q_1

IQR=5-1

IQR=4

The interquartile range of the data is 4. Therefore, option C is correct.

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This question is not complete.

Complete Question

Major arc CBD measures 300°. Which is the radian measure of its corresponding central angle?

a)4pi/3 radians

b) 5pi/6 radians

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d) 11pi/6 radians

Answer:

c) 5pi/3 radians = 5π/3 radians

Step-by-step explanation:

The corresponding central angle can be defined as the angle that is formed when there is a joining together of two radii at the center of the circle.

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360° = 2πr , radius is not given hence , 360° = 2π

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Cross multiply

360Y= (300× 2π)

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Y = (5π÷ 3) radians

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Answer:

The drawn in the attached figure

see the explanation

Step-by-step explanation:

<em>First case</em>

In the triangle ABC

Let

a=4\ units\\b=2/ units\\B=30^o

Applying the law of sines

Find the measure of angle A

\frac{a}{sin(A)}=\frac{b}{sin(B)}

substitute the given values

\frac{4}{sin(A)}=\frac{2}{sin(30^o)}

sin(A)=1

so

A=90^o

Find the measure of angle C

In a right triangle

we know that

B+C=90^o ----> by complementary angles

B=30^o

therefore

C=60^o

Find the length side c

Applying the law of sines

\frac{c}{sin(C)}=\frac{b}{sin(B)}

substitute the given values

\frac{c}{sin(60^o)}=\frac{2}{sin(30^o)}

c=2\sqrt{3}\ units

therefore

The dimensions of the triangle are

A=90^o

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C=60^o

a=4\ units\\b=2\ units\\c=2\sqrt{3}=3.46\ units

<em>Second case</em>

In the triangle ABC

Let

a=4\ units\\b=2/ units\\A=30^o

Applying the law of sines

Find the measure of angle B

\frac{a}{sin(A)}=\frac{b}{sin(B)}

substitute the given values

\frac{4}{sin(30^o)}=\frac{2}{sin(B)}

sin(B)=0.25

so

using a calculator

B=14.48^o

Find the measure of angle C

we know that

The sum of the interior angles in any triangle must be equal to 180 degrees

so

A+B+C=180^o

A=30^o\\B=14.48^o

therefore

30^o+14.48^o+C=180^o

C=135.52^o

Find the length side c

Applying the law of sines

\frac{c}{sin(C)}=\frac{a}{sin(A)}

substitute the given values

\frac{c}{sin(135.52^o)}=\frac{4}{sin(30^o)}

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therefore

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A=30^o

B=14.48^o

C=135.52^o

a=4\ units\\b=2\ units\\c=5.61\ units

see the attached figure to better understand the problem

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