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2 years ago

7

In basketball, hang time is the time that both of your feet are off the ground during a jump. The equation for hang time is t=2(

2h/32)^1/2, where t is the time in seconds, and h is the height of the jump, in feet.
Player 1 had a hang time of 0.9 s. Player 2 had a hang time of 0.8 s. To the nearest inch, how much higher did Player 1 jump than Player 2?
____in.
is it 8? because I solved the problem and player 1s jump height minus player 2 is 0.68 feet which is 8.16 inches?

1 answer:

devlian [24]2 years ago

4 0

<span>Player 1 jump than Player 2 i know this because if you look at the problem twice you see the 0.9 is bigger then 0.8</span>

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Three dimensional figures

aksik [14]

Answer:

3d figures - "a three-dimensional shape can be defined as a solid figure or an object or shape that has three dimensions – length, width and height. Unlike two-dimensional shapes, three-dimensional shapes have thickness or depth." -Google

Some Examples are...

- cones

-cylinders

-cubes

-sphere

Hope this helps!

4 0

2 years ago

108 divided by 9 times (-12) dived by 6 - (100 divided by 5)

Nataliya [291]

108 divided by 9 = 12 x -12 = -144 divided by 6 = -24 - (100 divided by 5) =

-24 - 20 = -44

answer= -44

3 0

2 years ago

Read 2 more answers

F(x)=3x 2 +9f, left parenthesis, x, right parenthesis, equals, 3, x, squared, plus, 9 and g(x)=\dfrac{1}{3}x^2-9g(x)= 3 1 x 2

34kurt

Answer:

$f(g(x)) = \frac{1}{3}x^4 - 18x^2 + 252$

$g(f(x)) = 3x^4 + 18x^2 + 18$

<em>f(x) and g(x) and not inverse functions</em>

Step-by-step explanation:

Given

$f(x) = 3x^2 + 9$

$g(x) = \dfrac{1}{3}x^2 - 9$

Required

Determine f(g(x))

Determine g(f(x))

Determine if both functions are inverse:

Calculating f(g(x))

$f(x) = 3x^2 + 9$

$f(g(x)) = 3(\frac{1}{3}x^2 - 9)^2 + 9$

$f(g(x)) = 3(\frac{1}{3}x^2 - 9)(\frac{1}{3}x^2 - 9) + 9$

Expand Brackets

$f(g(x)) = (x^2 - 27)(\frac{1}{3}x^2 - 9) + 9$

$f(g(x)) = x^2(\frac{1}{3}x^2 - 9) - 27(\frac{1}{3}x^2 - 9) + 9$

$f(g(x)) = \frac{1}{3}x^4 - 9x^2 - 9x^2 + 243 + 9$

$f(g(x)) = \frac{1}{3}x^4 - 18x^2 + 252$

Calculating g(f(x))

$g(x) = \dfrac{1}{3}x^2 - 9$

$g(f(x)) = \frac{1}{3}(3x^2 + 9)^2 - 9$

$g(f(x)) = \frac{1}{3}(3x^2 + 9)(3x^2 + 9) - 9$

$g(f(x)) = (x^2 + 3)(3x^2 + 9) - 9$

Expand Brackets

$g(f(x)) = x^2(3x^2 + 9) + 3(3x^2 + 9) - 9$

$g(f(x)) = 3x^4 + 9x^2 + 9x^2 + 27 - 9$

$g(f(x)) = 3x^4 + 18x^2 + 18$

Checking for inverse functions

$f(x) = 3x^2 + 9$

Represent f(x) with y

$y = 3x^2 + 9$

Swap positions of x and y

$x = 3y^2 + 9$

Subtract 9 from both sides

$x - 9 = 3y^2 + 9 - 9$

$x - 9 = 3y^2$

$3y^2 = x - 9$

Divide through by 3

$\frac{3y^2}{3} = \frac{x}{3} - \frac{9}{3}$

$y^2 = \frac{x}{3} - 3$

Take square root of both sides

$\sqrt{y^2} = \sqrt{\frac{x}{3} - 3}$

$y = \sqrt{\frac{x}{3} - 3}$

Represent y with g(x)

$g(x) = \sqrt{\frac{x}{3} - 3}$

Note that the resulting value of g(x) is not the same as $g(x) = \dfrac{1}{3}x^2 - 9$

<em>Hence, f(x) and g(x) and not inverse functions</em>

4 0

2 years ago

logan has 20 action figures.he is shipping them to a friend.He can only fit 3 action figure in a box.How many boxes will he need

adoni [48]

20/3= 6 2/3
6.66 rounds to 7
7 boxes

6 0

2 years ago

Read 2 more answers

Bald-faced hornets have a hive that is approximately cone-shaped, as shown in the image. One such hive has a radius of 15 inches

sineoko [7]

Answer:

Volume of the hive is 4712.4 square inches.

Step-by-step explanation:

Since hive has the shape of a cone with radius = 15 inches and height = 20 inches

Therefore, volume of the given cone = $\frac{1}{3}(\text{Area of the base})\times \text{height}$

Area of the circular base = πr²

Area = π(15)²

= 225π

Volume of the cone = $\frac{1}{3}(225\pi )\times{20}$

= 1500π

= 4712.39

≈ 4712.4 square inches

Therefore, volume of the hive is 4712.4 square inches.

7 0

2 years ago