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2 years ago

Which of the choices below follow an exponential pattern? Select all that apply.

2 answers:

7 0

The correct answers are the division of skin cells every half hour and the equation
y=4(3)ˣ.

The division of skin cells can be modeled by the equation
y=a(b)ˣ, where a is the initial number of cells and b is the fraction they are divided into (half, fourth, etc.)
Since x is an exponent, this is exponential.

This is the same reason the equation is exponential; x is the exponent.

The second choice, y=x², would be quadratic, since x is raised to the second power.
Driving at a constant rate is linear, due to the constant rate of change.
y=2x³ is cubic, since x is raised to the 3rd power.
The table would be linear, since there is a constant rate of change (up 3 over 1, a slope of 3).

quester [9]2 years ago

7 0

Answer:

The answers are A and C

Bruh Moment

You might be interested in

A television is 28.5 inches wide and 16 inches long.

Umnica [9.8K]

Answer:

33 in

Step-by-step explanation:

The Pythagorean theorem tells you ...

diagonal² = length² +width²

diagonal² = (16 in)² +(28.5 in)² = 1068.25 in²

diagonal = √(1068.25 in²) ≈ 32.684 in

The diagonal of the television is about 33 inches.

7 0

2 years ago

The fuel cost per hour for running a ship is approximately one half the cube of the speed (measured in knots) plus additional fi

andrezito [222]

Answer:

6 knots

Step-by-step explanation:

Let the speed be v knots

then time taken to cover 500 M = 500 / v hrs

fuel consumption /hr = 216 + 0.5v^3

let F be the fuel consumption for trip

= [500/v][216 + 0.5v^3]

= 500[216/v + 0.5v^2]

dF/dv = 500[ - 216/v^2 + v]

d^2F/d^2v = 500[432/v^3 + 1] , i.e. +ve

so setting dF/dv will give a minima

500[ -216/v^2 + v] = 0

or v = 216/v^2

or v^3 = 216

solving, we get v = [216]^(1/3) = 6 knots

7 0

2 years ago

You will note the wheel has 38 slots. There are two green slots (labeled 0, 00) and 36 slots which alternate red/black and are n

Zarrin [17]

Answer:

P(M) = 0.3158

Step-by-step explanation:

Data given in the question:

Total Slots = 38

Green Slots = 2 labelled (0, 00)

Red Slots = 18

Black Slots = 18

E = Ball lands on an even numbered slot

M = Ball lands in a slot that is numbered a multiple of 3

We are required to find the probability of event M. For that, we need to identify how many multiples of 3 are present on the wheel.

Multiples of 3 between 1-36 = 3, 6, 9, 12, 15, 18, 21, 24, 27, 30, 33, 36

There are a total of 12 slots numbered with multiples of 3.

P(M) = No. of slots numbered a multiple of 3 / Total no. of slots

= 12/38

P(M) = 0.3158 (rounded to four decimal places).

5 0

2 years ago

The loudness, L, measured in decibels (Db), of a sound intensity, I, measured in watts per square meter, is defined as L = 10 lo

butalik [34]

Answer:

The approximate loudness of a rock concert with a sound intensity of $10^{-1}$ is 110 Db.

Step-by-step explanation:

The loudness, L, measured in decibels (Db), of a sound intensity, I, measured in watts per square meter, is : $L=10 log (\frac{I}{I_0})$

$I_0=10^{-12}$

We are supposed to find What is the approximate loudness of a rock concert with a sound intensity of $10^{-1}$

So, $I = 10^{-1}$

Substitute the values in the formula :

$L=10 log (\frac{10^{-1}}{10^{-12}})$

$L=10 log (10^{11})$

L=110 Db

So, the approximate loudness of a rock concert with a sound intensity of $10^{-1}$ is 110 Db.

7 0

2 years ago

Read 2 more answers

The greatest common divisor of two positive integers less than $100$ is equal to $3$. Their least common multiple is twelve time

tangare [24]

Answer:

129

Step-by-step explanation:

Let a and b be two numbers.

We have been given that the greatest common divisor of two positive integers less than 100 is equal to 3. We can represent this information as $GCD(a,b)=3$ .

Their least common multiple is twelve times one of the integers. We can represent this information as $LCM(a,b)=12a$ .

Now, we will use property $GCD(x,y)*LCM(x,y)=xy$ .

Upon substituting our given values, we will get:

$3*12a=ab$

$36a=ab$

Switch sides:

$ab=36a$

$\frac{ab}{a}=\frac{36a}{a}$

$b=36$

Now, we need to find a number less than 100, which is co-prime with 12 after dividing by 3.

The greatest multiple of 3 less than 100 is 99, but it is not co-prime with 12 after dividing by 3.

Similarly 96 is also not co-prime with 12 after dividing by 3.

We know that greatest multiple of 3 (less than 100), which is co-prime with 12, is 93.

Let us add 36 and 93 to find the largest possible sum of the required two integers as:

$36+93=129$

Therefore, the required largest possible sum of the two integers is 129.

3 0

2 years ago