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ryzh [129]
2 years ago
5

You will note the wheel has 38 slots. There are two green slots (labeled 0, 00) and 36 slots which alternate red/black and are n

umbered 01-36. A player participates by tossing a small ball around the wheel as the wheel spins, and the ball lands in one of the 38 slots. The goal is for the ball to land in a slot that the player predicted it would, and bet money on happening. Define the following events: E = The ball lands in an even numbered slot M = The ball lands in a slot that is numbered a multiple of three (3, 6, 9, 12, etc...) Use the given information to calculate the probability of event M. Round your answer to four decimal places.
Mathematics
1 answer:
Zarrin [17]2 years ago
5 0

Answer:

<u>P(M) = </u><u>0.3158</u>

<u />

Step-by-step explanation:

<u>Data given in the question:</u>

Total Slots = 38

Green Slots = 2 labelled (0, 00)

Red Slots = 18

Black Slots = 18

E = Ball lands on an even numbered slot

M = Ball lands in a slot that is numbered a multiple of 3

We are required to find the probability of event M. For that, we need to identify how many multiples of 3 are present on the wheel.

Multiples of 3 between 1-36 = 3, 6, 9, 12, 15, 18, 21, 24, 27, 30, 33, 36

There are a total of<u> 12 slots numbered with multiples of 3</u>.

P(M) = No. of slots numbered a multiple of 3 / Total no. of slots

       = 12/38

P(M) = 0.3158 (rounded to four decimal places).

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The U.S. Bureau of Labor Statistics reports that 11.3% of U.S. workers belong to unions (BLS website, January 2014). Suppose a s
andrezito [222]

Answer:

a) Null hypothesis:p \leq 0.113  

Alternative hypothesis:p > 0.113  

b) z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

Replacing we got:

z=\frac{0.13 -0.113}{\sqrt{\frac{0.113(1-0.113)}{400}}}=1.074  

The p value for this case would be given by:

p_v =P(z>1.074)=0.141  

c) For this case we see that the p value is higher than the significance level of 0.05 so then we have enough evidence to FAIL to reject the null hypothesis and we can't conclude that the true proportion workers belonged to unions is significantly higher than 11.3%

Step-by-step explanation:

Information given

n=400 represent the random sample taken

X=52 represent the  workers belonged to unions

\hat p=\frac{52}{400}=0.13 estimated proportion of workers belonged to unions

p_o=0.113 is the value that we want to test

\alpha=0.05 represent the significance level

Confidence=95% or 0.95

z would represent the statistic

p_v represent the p value

Part a

We want to test if the true proportion of interest is higher than 0.113 so then the system of hypothesis are.:  

Null hypothesis:p \leq 0.113  

Alternative hypothesis:p > 0.113  

Part b

The statistic is given by:

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

Replacing we got:

z=\frac{0.13 -0.113}{\sqrt{\frac{0.113(1-0.113)}{400}}}=1.074  

The p value for this case would be given by:

p_v =P(z>1.074)=0.141  

Part c

For this case we see that the p value is higher than the significance level of 0.05 so then we have enough evidence to FAIL to reject the null hypothesis and we can't conclude that the true proportion workers belonged to unions is significantly higher than 11.3%

8 0
2 years ago
A sports statistician was interested in the relationship between game attendance (in thousands) and the number of
Luda [366]

Answer:

The predicted number of wins for a team that has an attendance of 2,100 is 25.49.

Step-by-step explanation:

The regression  equation for the relationship between game attendance (in thousands) and the number of  wins for baseball teams is as follows:

\hat y = 4.9\cdot x + 15.2

Here,

<em>y</em> = number of wins

<em>x</em> = attendance (in thousands)

Compute the number of wins for a team that has an attendance of 2,100 as follows:

\hat y = 4.9\cdot x + 15.2

  =(4.9\times 2.1)+15.2\\=10.29+15.2\\=25.49

Thus, the predicted number of wins for a team that has an attendance of 2,100 is 25.49.

4 0
2 years ago
ACME Manufacturing claims that its cell phone batteries last more than 32 hours on average in a certain type of cell phone. Test
son4ous [18]

Answer:

We can conclude that the battery life is greater than the 32 hour claim.

Step-by-step explanation:

The null hypothesis is:

H_{0} = 32

The alternate hypotesis is:

H_{1} > 32

Our test statistic is:

t = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}

In which X is the statistic, \mu is the mean, \sigma is the standard deviation and n is the size of the sample.

In this problem, we have that:

X = 37.8, \mu = 32, \sigma = 10, n = 18

So

t = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

t = \frac{37.8 - 32}{\frac{10}{\sqrt{18}}}

t = 2.46

We need to find the probability of finding a mean time greater than 37.8. If it is 5% of smaller(alpha = 0.05.), we can conclude that the battery life is greater than the 32 hour claim.

Probability of finding a mean time greater than 37.8

1 subtracted by the pvalue of z = t = 2.46.

z = 2.46 has a pvalue of 0.9931

1 - 0.9931 = 0.0069 < 0.05

So we can conclude that the battery life is greater than the 32 hour claim.

5 0
2 years ago
In a recent survey of dog owners, it was
siniylev [52]

Answer:

1749

Step-by-step explanation:

You would set up a proportion that says 901/x = 34/100. You would cross multiply to get that 34x = 90100. You would divide 90100 by 34 to get 2650. Then do 2650 - 901 to get 1749.

6 0
2 years ago
Adam plans to choose a video game from a section of the store where everything is 75% off. He writes the expression d−0.75d to f
alekssr [168]

Answer:

is 0.75d becase the missing numbers should be the same number

5 0
2 years ago
Read 2 more answers
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