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olchik [2.2K]
2 years ago
4

At a store, ice cream cones cost $1.80 and sundaes cost $3.30. One day the receipts for a total of 148 cones and sundaes were $3

60.90. How many cones were sold? How many sundaes?
Mathematics
1 answer:
valentina_108 [34]2 years ago
7 0

X= cones; y= sundaes

1.80x + 3.30y = 360.90 -------(i)

x + y = 148 -----------(ii)

from (ii) y= 148-x

1.80x + 3.30(148-x) = 360.9

1.80x + 488.4 + 3.30x = 360.9

1.5x = 127.5

x  = 85 cones



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adam and betty purchased a printer together for $258. If adam paid $18 less than twice betty, how much money did Adam pay for th
LenKa [72]

Answer:

Step-by-step explanation:

Let A = Adam, B = Betty

Adam and Betty purchased a printer together for $258.

This means we can say A + B = 258.

We are also told Adam paid $18 less than twice Betty.

You can write this as:

Adam = 2 x Betty - 18

A = 2B - 18

Substitute "A" into the A + B equation and you get:

A + B = 258

2B - 18 + B = 258

3B - 18 = 258

Add 18 to both sides.

3B = 258 + 18

3B = 276

Divide both sides by 3 to find B

B = 276/3 = 92 (This means Betty paid $92).

Since the total that they paid together was $258.

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4 0
2 years ago
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melamori03 [73]

Answer:

103.160 \leq \sigma \leq 187.476

And the upper bound rounded to the nearest integer would be 187.

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population mean or variance lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.

The Chi Square distribution is the distribution of the sum of squared standard normal deviates .

\bar X represent the sample mean for the sample  

\mu population mean (variable of interest)

s represent the sample standard deviation

n represent the sample size  

Solution to the problem

Data given: 114 157 203 257 284 299 305 344 378 410 421 450 478 480 512 533 545

The confidence interval for the population variance \sigma^2 is given by the following formula:

\frac{(n-1)s^2}{\chi^2_{\alpha/2}} \leq \sigma \leq \frac{(n-1)s^2}{\chi^2_{1-\alpha/2}}

On this case we need to find the sample standard deviation with the following formula:

s=sqrt{\frac{\sum_{i=1}^{17} (x_i -\bar x)^2}{n-1}}

And in order to find the sample mean we just need to use this formula:

\bar x =\frac{\sum_{i=1}^n x_i}{n}

The sample mean obtained on this case is \bar x= 362.941 and the deviation s=132.250

The next step would be calculate the critical values. First we need to calculate the degrees of freedom given by:

df=n-1=17-1=16

Since the Confidence is 0.90 or 90%, the value of \alpha=0.1 and \alpha/2 =0.05, and we can use excel, a calculator or a tabel to find the critical values.  

The excel commands would be: "=CHISQ.INV(0.05,16)" "=CHISQ.INV(0.95,16)". so for this case the critical values are:

\chi^2_{\alpha/2}=26.296

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And replacing into the formula for the interval we got:

\frac{(16)(132.250)^2}{26.296} \leq \sigma \leq \frac{(16)(132.250)^2}{7.962}

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Now we just take square root on both sides of the interval and we got:

103.160 \leq \sigma \leq 187.476

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Answer: Answer is B, -1

Step-by-step explanation:

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