For the answer to the question above, I think this is <span>False and the answer is based on the book, Nirenberg, and Matthaei. 19- unlabeled amino acids. Cys-Val-Cys-Val. (pg. 318 & 319)</span>. I hope I helped you somehow. Have a nice day!
Active transport moves small molecules against the a concentration gradient which is the opposite of diffusion or that's what i found in Quizlet
A conversational plan with two habitat preserves, measuring a total of 20 square kilometers combined will preserve more species because this cause segregation of species based on their adaptability towards a safer and secure environment. For example if a lion and deer try to live in the same conservation area, then it’s obvious that the life of deer is always at risk. But in cases of segregated preserved areas both herbivorous and carnivorous animals can live separately. Also if there is special inclination of one species towards other then also these two species can live separately.
Segregation also enhances the diversity in the sense that it could lead to a new ecosystem with a new ecological balance within it. Conservation biologists focus on these areas as they claim that where the greatest number of unique species can be found and protected with in the large number of reserve areas with the least amount of effort
Answer:
Explanation:
To calculate the recombination frequency, we have to know that 1% of recombinations = 1 map unit = 1cm. And that the maximum recombination frequency is always 50%.
The map unit is the distance between the pair of genes for which every 100 meiotic products, one of them results in a recombinant one.
So, en the exposed example:
- J and K are autosomal genes
- J and K are separated by 60 M.U.
- 60 M.U. means that there is 60% of recombination.
Cross) J K / j k x j k / j k
Gametes) JK Parental jk, jk, jk, jk
jk Parental
Jk Recombinant
jK Recombinant
One map unit equals 1% of recombination frequency. This means that every 100 meiotic products, one of them is a recombinant one.
1 M.U. -------------- 1% recombination
60 M.U. ------------ 60% recombination
30% Jk + 30% jK
100 M.U. - 60 M.U. = 40 M.U.
40M.U.--------------40 % Parental (Not recombinant)
20% JK + 20% jk
Punnet Square) JK jk Jk jK
jk JK/jk jk/jk Jk/jk jK/jk
J K / j k = 20%
j k / j k = 20%
J k / j k = 30%
j K / j k = 30%
Answer:
It helps the body regain iron from the blood loss that occurs during a surgery. Hope this helps :)
