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2 years ago

Find the smallest value of n such that the LCM of n and 15 is 45.

Mathematics

3 answers:

belka [17]2 years ago

6 0

Solution:

we have been asked to find

The smallest value of n such that the LCM of n and 15 is 45.

The prime factors of 15 are

$15=3*5$

So in LCM of n and 15 , we must include both the prime factors and the LCM is 45.

Since 3 is one time in the prime factor of 15. But to make 45 we need one more 3 and its possible if we take the value of n as below"

n=9

$9=3*3=3^2$

Hence the LCM will be

$3^2*5=45$

Hence the smallest possible value of n is 9.

Verdich [7]2 years ago

5 0

I hope this helps answer your question. i believe the answer is 5.

Guest1 year ago

0 0

Here prime factors of 45 =3x3x5
and factors of 15 = 3x5

Taking 3x3 as common factors with highest index = 9
Which is the value of n= 9

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We can deduce that this term will be located somewhere in the middle. So I will calculate $k= 5; k=6 \text{ and } k =7$ .

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