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Deffense [45]
2 years ago
15

Peter wants to purchase pizza pies and breadsticks for a party. The cashier tells him that pizza pies are $8 each and breadstick

s are $5 each. Peter cannot spend more than $120. Which of the following options models the number of pizza pies and breadsticks that Peter can purchase? Let y represent the number of pizza pies purchased and let x represent the number of breadsticks purchased. 5x + 8y ≤ 120 5x + 8y ≥ 120 8x + 5y ≤ 120 8x + 5y ≥ 120
Mathematics
2 answers:
kolezko [41]2 years ago
7 0
Apromixly this would equal 5x+8y<span>≤120</span>
sladkih [1.3K]2 years ago
6 0
The answer is 5x+8y<= 120
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Emily is a songwriter who collects royalties on her songs whenever they are played in a commercial or a movie. Emily will earn $
Hitman42 [59]

Answer:

(6,2)

Step-by-step explanation:

Variable Definitions:

​x= the number of commercials

y= the number of movies

Each commercial earns Emily $50, so x commercials would earn her 50x dollars in royalties. Each movie earns Emily $150, so y movies would earn her 150y dollars in royalties. Therefore, the total royalties 50x+150y equals $600:

50x+150y=600

Since Emily's songs were played on 3 times as many commercials as movies, if we multiply 3 by the number of movies, we will get the number of commercials, meaning x equals 3y.

x=3y

Write System of Equations:

​50x+150y=600

x=3y

Solve for y in each equation:

1)  50x+150y=600

   150y=−50x+600

   y=-1/3x+4

2)  x=3y

    y=1/3x

The x variable represents the number of commercials and the yy variable represents the number of movies. Since the lines intersect at the point (6,2) we can say:

Emily's songs were played on 6 commercials and 2 movies.

​

 

4 0
2 years ago
The graph of f(x) = x6 – 2x4 – 5x2 + 6 is shown below.
DochEvi [55]

Answer:

There are two rational roots for f(x)

Step-by-step explanation:

We are given a function

f(x) = x^6-2x^4-5x^2+6

To find the number of rational roots for f(x).

Let us use remainder theorem that when

f(a) =0, (x-a) is a factor of f(x) or x=a is one solution.

Substitute 1 for x

f(1) = 1-2-5+6=0

Hence x=1 is one solution.

Let us try x=-1

f(-1) = 1-2-5+6 =0

So x =-1 is also a solution and x+1 is a factor

We can write f(x) by trial and error as

f(x) = (x-1)(x+1)(x^2-3)

We find that f(x) (x^2-3) factor gives two irrational solutions as

±√3.

Hence number of rational roots are 2.

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2 years ago
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Answer:

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Step-by-step explanation:

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