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mihalych1998 [28]
2 years ago
4

Jane’s monthly income in the year 2010 was $48,200, where 14% of her salary was withheld for income tax. In the year 2011, her m

onthly salary was $51,800, where 16% of her income was withheld for income tax. What was her average take home pay during the years 2010-2011?
Mathematics
2 answers:
Ne4ueva [31]2 years ago
8 0
<h2>Answer:</h2>

The average take home pay per month during the years 2010-2011 was $42,482.

<h2>Step-by-step explanation:</h2>

Jane’s monthly income in the year 2010 was $48,200, where 14% of her salary was withheld for income tax.

So, for the year 2010, the amount withheld was = 0.14\times48200=6748 dollars.

Her take home salary was = 48200-6748=41452 dollars

This is the monthly pay so her yearly pay is 12\times41452=$497424

==================================================

In the year 2011, her monthly salary was $51,800, where 16% of her income was withheld for income tax.

So, for the year 2011, the amount withheld was = 0.16\times51800=8288 dollars.

Her take home salary was = 51800-8288=43512 dollars

Her yearly pay is 12\times43512=$522144

===================================================

So, her average take home pay per month during the years 2010-2011 was:

\frac{497424+522144}{24} = $42,482.

Amanda [17]2 years ago
4 0
In 2010: Take home salary = (1-0.14)*(48200*12) = $497,424
In 2011: Take home salary = (1-0.16)*(51800*12) = $522,144

Average take home per month in 2010-11 = (497,424+522,144)/24 = $42,482
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