Hey :))
(-p,-q)(p,q)slope = (q - (-q) / (p - (-p) = (q + q) / (p + p) = 2q / 2p = q/p
y = mx + b.....slope(m) = q/p(p,q)...x = p and y = qnow we sub and find b, the y intq = (q/p)(p) + bq = q + bq - q = b0 = b
so ur equation is : y = (q/p)x + 0...or just y = (q/p)x....its answer B
HOPE THIS HELPED!!! :))
I believe the correct answers are:
<span>UV = 14 ft and m∠TUV = 45°</span>
<span>ST = 20 ft, UV = 14 ft, and m∠UST = 98°
Or, in other words, Options A and D.
</span>
We know that
volume of <span>a rectangular prism =B*h------> equation 1
where
B is the area of the base
h is the height
volume of </span><span>a rectangular pyramid=(1/3)*B*h-----> equation 2
where
</span>B is the area of the base
h is the height
<span>
substitute equation 1 in equation 2
</span>volume of a rectangular pyramid=(1/3)*volume of a rectangular prism
<span>
the answer part a) is
</span>volume of a rectangular pyramid=(1/3)*volume of a rectangular prism
<span>
Part b) </span><span>If the pyramid was full of water, how much of the prism would it fill up?
</span>
the answer part b) is
<span>If the pyramid was filled with water, the prism would only fill 1/3 of its volume
Part c) </span><span>Name another pair of three-dimensional objects that have a relationship similar to this
cones and cylinders
</span>volume of a cylinder =B*h------> equation 1
where
B is the area of the base
h is the height <span>
</span>volume of a cone=(1/3)*B*h-----> equation 2
where
B is the area of the base
h is the height
substitute equation 1 in equation 2
volume of a cone=(1/3)*volume of a cylinder
A graphing calculator shows the rocks are at the same height 1.5 seconds after they are released.
That height is 3.975 meters.
_____
f(x) = g(x)
-4.9x^2 +15 = -4.9x^2 +10x
15 = 10x . . . . . . . . . . . . . . . . . . add 4.9x^2
1.5 = x . . . . . . . . . . . . . . . . . . . divide by 10
f(1.5) = -4.9*2.25 +15 = 3.975
If two chords of a circle are congruent, then their intercepted arcs are congruent
7x-39 = 87
7x = 87 + 39
7x = 126
x = 126/7
x = 18
