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2 years ago

What is the most direct use of a compass in geometric constructions?

Mathematics

2 answers:

Dmitry_Shevchenko [17]2 years ago

6 0

The <em>correct answer</em> is:

To draw arcs of a given size.

Explanation:

A compass is a tool used to draw a circle. Since an arc is a part of a circle, the most direct use of a compass would be to draw arcs of a given size.

chubhunter [2.5K]2 years ago

5 0

The most direct use of a compass in any geometric constructions are to draw arcs of a given size. The correct answer is B.

You might be interested in

What's 5/6 as a decimal rounded to the nearest hundredth

zaharov [31]

Hello there!

the answer is 8.33

Hope I helped!

Let me know if you need anything else!

~ Zoe

4 0

2 years ago

For the binomial expansion of (x + y)^10, the value of k in the term 210x 6y k is a) 6 b) 4 c) 5 d) 7

Sloan [31]

Answer:

a) 6

Step-by-step explanation:

Expanding the polynomial using the formula:

$(x+y)^n=\sum_{k=0}^n \binom{n}{k} x^{n-k} y^k$

Also

$\binom{n}{k}=\frac{n!}{(n-k)!k!}$

I think you mean $210x^6y^4$

We can deduce that this term will be located somewhere in the middle. So I will calculate $k= 5; k=6 \text{ and } k =7$ .

For $k=5$

$\binom{10}{5} (y)^{10-5} (x)^{5}=\frac{10!}{(10-5)! 5!}(y)^{5} (x)^{5}= \frac{10 \cdot 9 \cdot 8 \cdot 7 \cdot 6 \cdot 5! }{5! \cdot 5 \cdot 4 \cdot 3 \cdot 2 \cdot 1 } \\ =\frac{30240}{120} =252 x^{5} y^{5}$

Note that we actually don't need to do all this process. There's no necessity to calculate the binomial, just $x^{n-k} y^k$

For $k=6$

$\binom{10}{6} \left(y\right)^{10-6} \left(x\right)^{6}=\frac{10!}{(10-6)! 6!}\left(y\right)^{4} \left(x\right)^{6}=210 x^{6} y^{4}$

5 0

2 years ago

A label that wraps around a box of golf balls covers 75% of its lateral surface area. What is the value of x? The height is 2 th

GalinKa [24]

To find the area of the rectangular prism, use the formula:

A = width x height x length

A = 2 x 2 x 3

A = 12

Now multiply A with 0.75

12 x 0.75 = 9

x = 9 in³

hope this helps

5 0

2 years ago

Read 2 more answers

1. Contaminated water is subjected to a cleaning process. The concentration of the pollutants is initially 5 mg per liter of wat

Art [367]

Answer:

$C(t)=5\cdot(0.9)^t$

Step-by-step explanation:

The exponential function is often used to model natural growing or decaying processes, where the change is proportional to the actual quantity.

An exponential decaying function is expressed as:

$C(t)=C_o\cdot(1-r)^t$

Where:

C(t) is the actual value of the function at time t

Co is the initial value of C at t=0

r is the decaying rate, expressed in decimal

The concentration of the pollutants starts at Co=5 mg/lt. We also know the pollutant reduces its concentration by 10% each hour. This gives us a value of r = 10% / 100 = 0.1

Substituting into the general equation:

$C(t)=5\cdot(1-0.1)^t$

Operating:

$\boxed{C(t)=5\cdot(0.9)^t}$

7 0

2 years ago

A publishing company prints newspapers and magazines. Let NNN represent the number of newspapers and MMM represent the number of

adelina 88 [10]

Answer:

At most 800 magazines the company can print daily with the remaining number of ink cartridges.

Step-by-step explanation:

We are given the following in the question:

$0.5N+2.5M \leq 6000$

The above inequality gives the relation for daily supply of ink cartridges where N is the number of newspaper and M is the number of magazines.

Number of newspaper to be printed daily,N = 8000

We have to find the number of magazines at most can the company print daily with the remaining number of ink cartridges.

Puting the value in the given inequality,

$0.5(8000)+2.5M \leq 6000\\\Rightarrow 4000+2.5M \leq 6000\\\Rightarrow 2.5M \leq 2000\\\\\Rightarrow M \leq \dfrac{2000}{2.5}\\\\\Rightarrow M \leq 800$

Thus, at most 800 magazines the company can print daily with the remaining number of ink cartridges.

6 0

2 years ago