Answer/Step-by-step explanation (ac > b² or b² < ac.
)
A/c to question, we have to show:-
b² >ac in A.P ........ (1)
b² = ac in G.P .....(2)
b² < ac in H.P. ..... (3)
b = a+c/2 (A.P)
b = √ac ( G.P)
b = 2ac/a+c (H.P)
In A.P :
b² > ac = b² - ac
= (a+c/2)² - ac
= (a²+2ac+c²/4) - ac = a² + 2ac + c² - 4ac / 4
= a² - 2ac + c² / 4 = ( a - c ) ² / 4 > 0 Hence, b²>ac
In G.P:-
b = √ac
Hence, b² = ac
In H.P :- b² < ac = ac > b² = ac - b² = ac - ( 2ac / a+c)
= ac(a+c) - 2ac / a+c
= a²c + ac² - 2ac / a+c
= ac(2ac - 2) / a+c > 0
Hence, ac > b² or b² < ac.
Answer:
C
Step-by-step explanation:
When you move the decimal either to the right or the left, you change the value. To divide any number by 10, move the decimal point one place to the left. For example:
0.7
7
70
700
7,000
So, for any decimal, when you move the decimal point one place to the right, you multiply that number by 10.
Answer:
No you can't because just like multiplication, you cant divide anything by zero.
Step-by-step explanation:
You must evaluate the function f first. Division by 0 is undefined.
Therefore, The composition cannot be evaluated.
