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2 years ago

The rational roots of a polynomial function F(x) can be written in the form p/q,

Mathematics

1 answer:

11Alexandr11 [23.1K]2 years ago

7 0

ANSWER

True

EXPLANATION

According to the Rational Roots Theorem,the rational roots of a polynomial function F(x) can be written in the form

$\frac{p}{q}$

where p is a factor of the constant term of the polynomial, and q is a factor of the leading coefficient.

The polynomial must be written in standard form.

This means the polynomial must be written in descending powers of x.

The leading term is the first term of a polynomial written in standard form.

The constant term is the term independent of x.

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GrogVix [38]

Answer:

9/20, or 0.45 mile.

Step-by-step explanation: $\\$

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2 years ago

destiny sells pencil cases for $5 each and mechanical pencils for $2 each at the school supply store. she sells p pencil cases a

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Answer:

Step-by-step explanation:

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2 years ago

Which are the solutions of x2 = –5x + 8? StartFraction negative 5 minus StartRoot 57 EndRoot Over 2 EndFraction comma StartFract

serg [7]

Answer:

$x=\frac{-5-\sqrt{57} }{2}\ or\ x=\frac{-5+\sqrt{57} }{2}$

Step-by-step explanation:

Given:

The equation to solve is given as:

$x^2=-5x+8$

Rearrange the given equation in standard form $ax^2+bx +c =0$ , where, $a,\ b,\ and\ c$ are constants.

Therefore, we add $5x-8$ on both sides to get,

$x^2+5x-8=0$

Here, $a=1,b=5,c=-8$

The solution of the above equation is determined using the quadratic formula which is given as:

$x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

Plug in $a=1,b=5,c=-8$ and solve for $x$ .

$x=\frac{-5\pm \sqrt{5^2-4(1)(-8)}}{2(1)}\\x=\frac{-5\pm \sqrt{25+32}}{2}\\x=\frac{-5\pm \sqrt{57}}{2}\\\\\\\therefore x=\frac{-5-\sqrt{57} }{2}\ or\ x=\frac{-5+\sqrt{57} }{2}$

Therefore, the solutions are:

$x=\frac{-5-\sqrt{57} }{2}\ or\ x=\frac{-5+\sqrt{57} }{2}$

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2 years ago

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vovikov84 [41]

Triangles ABC and DEF may or may not be congruent, because the angle-angle-angle (AAA) postulate is not a criterion for congruency of any two triangles. This is because the angle-angle-angle postulate only incorporates the angles of the triangles, and the side lengths are not specified, so congruency may or may not be true for these triangles.

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