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Dafna11 [192]
2 years ago
11

Simplify 3.2-5.1n-3n+5

Mathematics
2 answers:
Shtirlitz [24]2 years ago
5 0
The answer is 
-8.1n+8.2
dimaraw [331]2 years ago
4 0
To do this you have to combine terms that are alike

3.2+5= 8.2
-5.1n-3n= -8.1n

Now you combine the two and get an answer of -8.1n-8.2
You might be interested in
The fuel cost per hour for running a ship is approximately one half the cube of the speed (measured in knots) plus additional fi
andrezito [222]

Answer:

6 knots

Step-by-step explanation:

Let the speed be v knots

then time taken to cover 500 M = 500 / v hrs

fuel consumption /hr = 216 + 0.5v^3

let F be the fuel consumption for trip

= [500/v][216 + 0.5v^3]

= 500[216/v + 0.5v^2]

dF/dv = 500[ - 216/v^2 + v]

d^2F/d^2v = 500[432/v^3 + 1] , i.e. +ve

so setting dF/dv will give a minima

500[ -216/v^2 + v] = 0

or v = 216/v^2

or v^3 = 216

solving, we get v = [216]^(1/3) = 6 knots

7 0
2 years ago
One number is 5 more than another. the difference between their squares is 155. what are the numbers
kirza4 [7]

the smaller number is 13 and the larger one is 18.

Let's say that the smaller number is x and the larger one is y.

Giving the equation x + 5 = y

This would also make the equation y^2-x^2= 155

to solve let's simplify to find what y^2 is in x terms.

y^2 = (x+5) (x+5) = x^2 +10x + 25.

therefore x^2 + 10x + 25 -x^2= 155

10x + 25 = 155

10x = 130

x = 13

y = 18

5 0
2 years ago
Arrange the entries of matrix A in increasing order of their cofactors values
givi [52]

To find the cofactor of

A=\left[\begin{array}{ccc}7&5&3\\-7&4&-1\\-8&2&1\end{array}\right]

We cross out the Row and columns of the respective entries and find the determinant of the remaining 2\times 2 matrix with the alternating signs.


Ac_{11}=\left|\begin{array}{ccc}4&-1\\2&1\end{array}\right|


Ac_{11}=4\times 1- -1\times 2


Ac_{11}=4+ 2

Ac_{11}=6




Ac_{12}=-\left|\begin{array}{ccc}-7&-1\\-8&1\end{array}\right|


Ac_{12}=-(-7\times 1- -1\times -8)


Ac_{12}=-(-7- 8)

Ac_{12}=15




Ac_{21}=-\left|\begin{array}{ccc}5&3\\2&1\end{array}\right|


Ac_{21}=-(5\times 1- 3\times 2)


Ac_{21}=-(5-6)


Ac_{21}=1







A_c{23}=-\left|\begin{array}{ccc}7&5\\-8&2\end{array}\right|


Ac_{23}=-(7\times 2 -8\times 5)


Ac_{23}=-(14-40)


Ac_{23}=26




A_c{31}=\left|\begin{array}{ccc}5&3\\4&-1\end{array}\right|


Ac_{31}=5\times -1 -4\times 3


Ac_{31}=-5-12


Ac_{31}=-17


A_c{33}=\left|\begin{array}{ccc}7&5\\-7&4\end{array}\right|


Ac_{33}=7\times 4- -7\times 5


Ac_{33}=28+35


Ac_{33}=63


Therefore in increasing order, we have;

Ac_{31}=-17,Ac_{21}=1,Ac_{11}=6,Ac_{23}=26,Ac_{12}=15, Ac_{33}=63



7 0
2 years ago
Read 2 more answers
Forty more than twice malia's age is 64
ICE Princess25 [194]
12 x 2+40=64

Malia is 12 years old.


8 0
2 years ago
Read 2 more answers
If a circle has a circumference of 6.28 inches, then what is the radius?
Gnesinka [82]
The radius would be 1in.
5 0
2 years ago
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