1. DNA unzips in the nucleus.
RNA polymerase binds to the DNA sequence, separates the two strands and creates a single-stranded DNA molecule that will be transcripted.
2. Transcription occurs.
Transcription is the first step of gene expression. During this process, a gene's DNA sequence is copied and a mRNA molecule is produced.
3. mRNA moves to the ribosome
The mRNA is then transferred from the nucleus to the ribosome, the organelle that serves as a site for protein synthesis.
4. Translation occurs
Translation is the process where a mRNA sequence into the amino acid sequence of a polypeptide (protein).
5. Protein assembled at ribosome.
Translation, meaning the formation of a protein, occurs on the ribosome.
As a mechanism of evolution, natural selection can be most closely equated with UNEQUAL REPRODUCTIVE SUCCESS.
Mechanism of evolution refers to micro-evolution that involves mutation, gene flow and natural selection. Unequal reproductive success is also related to other processes of micro evolution such as natural selection. The organisms that can reproduce unequally and survive even in adverse condition, increase in numbers.
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Muscles pectoralis, an enormous muscle that ventilates beginning from shoulder to breastbone. The serratus foremost is named for its connection deep down and its source and muscle filaments. The pectoralis major is named for its size and area in the body.
Answer:
5- action potential 6- receptors 7- calcium ions 8- sarcolemma
Explanation:
This description illustrates the pathway of a action potential traveling along a neuro-muscular junction. this functions as a chemical synapse between a motor neuron and a muscle fibre. It allow the motor neuron to transmit a signal/action potential to the muscle fiber, causing muscle contraction.
Answer:
C. 1/4
Explanation:
Let's assume that the allele for the spotted coat is "S" and the one for the even coat is "s". The allele "L" gives short horns while the recessive allele "l" imparts long horns. The genotype of the cattle heterozygous for both traits would be SsLl. A cross between two heterozygous cattle would produce progeny in following phenotype ratio=
9 spotted coat and short horns: 3 even coat and short horns: 3 spotted coat and long horns: 1 even coat and long horns.
Therefore, the proportion of the progeny with long horns = 4/16= 1/4
