All categories

2 years ago

In the diagram below what is the approximate length of the minor arc XY

Mathematics

2 answers:

Ymorist [56]2 years ago

7 0

Answer:

B. 6.3 cm

Step by step explanation:

We have been given measure of central angle which intercepts to our minor arc XY.

Since we know that the formula to find measure of arc length is:

$\text{Arc length}=\frac{\theta}{360}\times \text{circumference of circle}$

$\text{Arc length}=\frac{\theta}{360}\times {2\pi r}$

Now let us substitute our given values in above formula.

$\theta=40^{o}$ and $radius=9 cm$

$\text{Arc length}=\frac{40}{360}\times {2\pi \cdot 9}$

$\text{Arc length}=\frac{1}{9}\times {2\pi \cdot 9}$

$\text{Arc length}=2 \pi$

$\text{Arc length}=6.2831853071795865\approx 6.3$

Therefore, length of minor arc XY is 6.3 cm and option B is the correct choice.

GalinKa [24]2 years ago

3 0

The answer is B.

The formula for arc length is s = r(theta) Theta must be in radians, so convert 40 degrees to radians, which is 2pi/9. Multiply 2pi/9 by the radius, 9, and then you'll get the answer. Hopes this helps!

You might be interested in

Alicia records the total number of points scored in two games by 10 players on her basketball team. 28, 13, 4, 8, 15, 10, 22, 7,

madam [21]

Answer:

Choices are missing here.

However, we can find the plot that represents the data.

To draw a scatterplot, we just need to draw points, where the indepedent variable is going to be 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, that is the position of each player.

So, all points we need to draw the plot are:

(1, 28)

(2, 13)

(3, 4)

(4, 8)

(5, 15)

(6, 10)

(7, 22)

(8, 7)

(9, 11)

(10, 15)

The image attached shows the plot that represents this data set.

6 0

2 years ago

Read 3 more answers

What are the x-intercepts of the function f(x) = –2x2 – 3x + 20?

Hatshy [7]

The root sof this quadratic equation are -4 and 2.5.

The roots of any quadratic can be found by using the quadratic equation. The equation is below for you.

$\frac{-b +/- \sqrt{b^{2}- 4ac}}{2a}$

In this equation you use the number attached to x^2 as the a, which in this case is -2. The number attached to x as b, which is in this case -3. And the number at the end as c, which is 20. From there you solve for the answers.

$\frac{3 +/- \sqrt{-3^{2}- 4(-2)(20)}}{2(-2)}$

$\frac{3 +/- \sqrt{9 + 160}}{-4}$

$\frac{3 +/- 13}}{4}$

Now you separate and get the two separate answers. First the positive.

$\frac{3 + 13}}{4}$

$\frac{16}}{4}$

Now the negative

$\frac{3 - 13}}{4}$

$\frac{-10}}{4}$

-2.5

5 0

2 years ago

Read 2 more answers

Based only on the information given in the diagram which congruence theorems or postulates could be givenas reasons why triangle

Evgesh-ka [11]

The answer is C, E, and F on Apex

3 0

2 years ago

Read 2 more answers

ANSWER ALL 5 PARTS.

N76 [4]

A function $f$ from a set A to a set B is defined as a relation that assings to each element $x$ in the set A exactly one element $y$ in the set B. The set A is called the domain of the function while the set B is the range. So we have five statements and need to find some functions. Melissa decides to reserve a patch in her vegetable garden for growing bell peppers. If each side of the tomato patch is $x$ feet, then we have a square patch as shown in the Figure below.

1.a) Write the function Wa(x) representing the width of the bell pepper patch.

We know that she wants its width to be half the width of the tomato patch. Let $x$ be the width of the tomato patch, then the function that matches this statement is:

$\boxed{Wa(x)=\frac{x}{2}}$

1.b) Write the function La(x) representing the length of the bell pepper patch.

In this case Melissa wants its length to exceed the length of the tomato patch by 2 feet. To do this we enlarge the length of the tomato patch 2 feet. Therefore the function is the following:

 $\boxed{La(x)=x+2}$

2. Area of the bell pepper patch in terms of x.

Given that the bell pepper patch is a rectangle, then the area of a rectangle is the product of the length and width. So:

 $A=(\frac{x}{2})(x+2) \\ \\ \therefore \boxed{A=\frac{x(x+2)}{2}}$

3. Combined area of the tomato patch and the bell pepper patch.

This function is the sum of both the area of the tomato patch and the bell pepper patch. So:

 $Aar(x)=x^{2}+\frac{x(x+2)}{2} \rightarrow Aar(x)=x^{2}+ \frac{x^{2}}{2}+x \rightarrow Aar(x)=\frac{3x^{2}}{2}+x \\ \\ \therefore \boxed{Aar(x)=\frac{x(3x+2)}{2}}$

4. Write the function Aa(x) for the remaining planting area in the garden.

The remaining planting area in the garden are the rectangles in red. So we need to subtract the width of the bell pepper patch from the width of the tomato patch and multiply it by 2. In mathematical language this is given by:

 $Aa(x)=2(x-\frac{x}{2}) \rightarrow Aa(x)=x$

5. Find the area of the remaining space in the garden after planting tomatoes and bell peppers.

Given that Melissa wants the area of the bell pepper patch to be 31.5 square feet, then it is true that:

 $31.5=\frac{x(x+2)}{2} \rightarrow x^{2}+2x-64=0 \\ \\ solving \ for \ x: \\ x=7.06$

Therefore the area of the remaining space is:

 $\boxed{Aa(7.06)=7.06ft^{2}}$

6 0

2 years ago

Explain how to draw a trend line for a scatterplot using the divide-center of data method.

Korvikt [17]

Before you can draw a trend line in your data, you should have a given data at hand. And then draw the trend line or line of best fit.

1. Plot your data in a graphing paper or excel.
2. Make sure that your plotted data has a solid mark to indicate the points in the graph.
3. Divide your data points by labeling x at the center, at the farthest part of your line (left or right diagonally).
4. If you feel that the data are now finely divided, then construct a line base on the x marks you're placing
5. Then you will notice how far or near your date points are by simply looking at the points near the constructed line that you created.

6 0

2 years ago

Read 2 more answers