the maximum height is the y-value of the vertex.
h(x) = -2x² + 20x + 48
<em> a=-2, b=20, c=48</em>

h(5) = -2(5)² + 20(5) + 48
= -50 + 100 + 48
= 50 + 48
= 98
Answer: 98 meters
The answer is four because if you lose two from the four you had you will still have a least 2 hope This helped
Answer:
The correct options are;
1) ΔBCD is similar to ΔBSR
2) BR/RD = BS/SC
3) (BR)(SC) = (RD)(BS)
Step-by-step explanation:
1) Given that RS is parallel to DC, we have;
∠BDC = ∠BRS (Angles on the same side of transversal)
Similarly;
∠BCD = ∠BSR (Angles on the same side of transversal)
∠CBD = ∠CBD = (Reflexive property)
Therefore;
ΔBCD ~ ΔBSR Angle, Angle Angle (AAA) rule of congruency
2) Whereby ΔBCD ~ ΔBSR, we therefore have;
BC/BS = BD/BR → (BS + SC)/BS = (BR + RD)/BR = 1 + SC/BS = RD/BR + 1
1 + SC/BS = 1 + RD/BR = SC/BS = 1 + BR/RD - 1
SC/BS = RD/BR
Inverting both sides
BR/RD = BS/SC
3) From BR/RD = BS/SC the above we have by cross multiplication;
BR/RD = BS/SC gives;
BR × SC = RD × BR → (BR)(SC) = (RD)(BR).
First of all, lets consider that you made a litte mistake and you meant this problem.........
<span>"The combined average weight of an okapi and a llama is 450 kilograms. The average weight of 3 llamas is 190 kilograms more than the average weight of one okapi. On average, how much does an okapi weigh, and how much does a llama weigh?"
This is a system of two equations.
Let it be X the average weight of a LLAMA
And Y the average weight of an OKAPI
X + Y = 450 kg 1)
3X = 190 kg +Y 2)
So, with 1) we have that Y = 450 - X
We subsitute in 2) and we have
3X = 190 + (450 -X).............We solve for X ....==> 4X = 640kg ==> X = 160kg
..We replace X in 1 and get => Y = 450kg -X = 450kg -160kg = 290kg
</span>160kg....... average weight of a LLAMA
290kg........average weight of an OKAPI